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3 years ago

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The length of a side of a triangle is 26 in. A line, parallel to the given side ,divides the triangle into 2 parts of equal area

s. Find the length of the segment cut from the line by the two other sides of the triangle

2 answers:

Ugo [173]3 years ago

7 0

Answer:

13 $\sqrt{2}$

elena-14-01-66 [18.8K]3 years ago

4 0

Answer:

13√ 2

Step-by-step explanation:

√ 26*(26/2)

=√ 26*13 = √ 338 = 13√ 2

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Juan decided to start saving for college. He deposited $500 into an account which earns 4% simple annual interest. At the end of

Norma-Jean [14]

Answer:

$5504

Step-by-step explanation:

Given that :

Principal amount = $500

Interest = 4% simple interest annually

Amount added at the end of each year :

First year:

Principal + (Principal * rate * time)

500 + (500 * 0.04) = 520

$520 + $250 = $770

2nd year:

770 + (770 * 0.04) = $800.80

$800.80 + $250 = 1050.80

3rd year:

1050.8 + (1050.8 * 4) = 5254

$5254 + 250 = $5504

5 0

3 years ago

The probability that a high school student in in the marching band is 0.47. The probability that a student plays a varsity sport

IrinaK [193]

The probability that a high school student in in the marching band is 0.47

so, $P(M)=0.47$

The probability that a student plays a varsity sport is 0.32

so, $P(V)=0.32$

the probability that a student is in the marching band and plays a varsity sport is 0.24

so, we get

P(M∩V)=0.24

a student plays a varsity sport if we know she is in the marching band

so,

P(V|M)=(P(V∩M))/(P(M))

now, we can plug values

and we get

$P(V|M)=\frac{0.24}{0.47}$

$P(V|M)=0.51063$

So,

the probability that a student plays a varsity sport if we know she is in the marching band is 0.51063......Answer

8 0

3 years ago

Read 2 more answers

Aubrey is going to see a movie and is taking her 2 kids. Each movie ticket costs $13 and there are an assortment of snacks avail

iren [92.7K]

Answer:

$51

Step-by-step explanation:

do 13*3 because of the 2 kids and the adult then add 12 because of the snacks

hope this helps

7 0

3 years ago

Read 2 more answers

Write an equation of the line in slope intercept form that goes through the points (-1,2) and (4,12) Show your work!

NemiM [27]

Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. To find b, you first need to calculate slope and see where the line intersects the y-axis.
To get m (slope), use the form y1 - y2/x1 - x2. It would look like this:
2 - 12/-1 - 4. This simplifies to:
-10/-5, which further simplifies to 2. Now, graph the points to find y....
My graph shows that the line intersects at (0, 4), so slope-intercept form would look like:
y = 2x + 4 (remember, 2 is the slope and 4 is the y-intercept)

Hope this helps.

5 0

4 years ago

1) Given P(A) = 0.3 and P(B) = 0.5, do the following.

Delicious77 [7]

Answer:

1) a) 0.8

b) 0.6

2) a) 0.08

b) 0.14

Step-by-step explanation:

1) Given

$P(A) = 0.3$ and $P(B) = 0.5$

Let us learn about a formula:

$P(A\ or\ B) = P(A) +P(B) -P(A\ and\ B)\\OR\\P(A\cup B) = P(A) +P(B) -P(A\cap B)$

(a) If A and B are mutually exclusive i.e. no common thing in the two events.

In other words:

$P(A\ and\ B)$ = $P(A \cap B)$ = 0

Using above formula:

$P(A\ or\ B) = P(A) +P(B) -P(A\ and\ B)\\\Rightarrow P(A\ or\ B) = 0.3 + 0.5 -0 = \bold{0.8}$

(b) P(A and B) = 0.2

Using above formula:

$P(A\ or\ B) = P(A) +P(B) -P(A\ and\ B)\\\Rightarrow P(A\ or\ B) = 0.3 + 0.5 -0.2 = \bold{0.6}$

*************************************

1) Given

$P(A) = 0.4$ and $P(B) = 0.2$

Let us learn about a formula:

$P(A\ and\ B) = P(B) \times P(A/B)$ for dependent events

$P(A\ and\ B) = P(A) \times P(B)$ for independent events.

(a) If A and B are independent events :

Using the above formula for independent events:

$P(A\ and\ B) = 0.4 \times 0.2 = \bold{0.08}$

(b) $P(A / B) = 0.7$

Using above formula:

$P(A\ and\ B) = P(B) \times P(A/B) = 0.2 \times 0.7 = \bold{0.14}$

6 0

3 years ago