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Svet_ta [14]
3 years ago
8

a shoe store has a sale in which all shoes are priced at $33.00. the original price was $44. what is the percent of discount. ​

Mathematics
1 answer:
Helen [10]3 years ago
5 0

Answer:

44 - 33 = 11

11/44 X 100 = 25%

Step-by-step explanation:

find the difference between the original price and new price (change)

change/original price X 100 = percentage change

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Twelve people in a group are left-handed.
tester [92]

Answer:

60 people

Step-by-step explanation:

Let

x = total people in the group

Number of Left-handed people = 12

Percentage of left-handed people = 20%

20% of x = 12

20/100 * x = 12

0.2 * x = 12

0.2x = 12

x = 12/0.2

x = 60 people

x = total people in the group = 60

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In this diagram, lines AC and DE are parallel and line DC is perpendicular to each of them. What is a reasonable estimate for th
igomit [66]

The reasonable estimate for the length of side DE is 3 units

Find the diagram of the question attached. The given triangle ABC and BDE are similar triangles.

Using the similarity theorem of a triangle, this is expressed as:

AC = DE

Using the pythagoras theorem to get the length of AC:

AB^2 = AC^2 + BC^2

5^2 + AC^2 + 4^2

AC^2 = 25 - 16

AC^2 = 9

AC= 3

Since AC = DE, hence the reasonable estimate for the length of side DE is 3 units

Learn more on similar shapes here: brainly.com/question/14285697

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Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
4 years ago
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