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elena-14-01-66 [18.8K]
2 years ago
11

PLEASE ANSWER!!!!!! 3 quarters, 3 dimes, and 5 pennies as fraction and decimal

Mathematics
1 answer:
Radda [10]2 years ago
8 0

Answer:

0.75 3/4, 0.30 3/10, 0.05 1/20

Step-by-step explanation:

25x3 is 75 but because its 75 cents its 0.75
and 3/4 means 0.75 (3 divided by 4 is 0.75)

10x3 is 30 but because its 30 cents its 0.30
and 3/10 means 0.30 (3 divided by 10 is 0.30)

1x5 is 5 and because its 5 cents its 0.05
and 1/20 means 0.05 (1 divided by 20 is 0.05)

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Answer<br> -5 &lt; ___<br> A.-10<br> B.0
-BARSIC- [3]

Answer:

B. 0

Step-by-step explanation:

The < sign means whatever is on the right side of the symbol should be greater than whatever is on the left side.

To solve this we need to understand that 0 is greater than -10. Then we need to make sure that 0 is greater than -5 and it is greater than -5.

Therefore the answer is 0

Hope this helps! If you have any more questions or need further clarification on anything please comment down below or message me! Good luck!

5 0
3 years ago
3.14 The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable with cumula
vovangra [49]

Answer:

(a) The probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function is 0.7981.

(b) The probability of waiting less than 12 minutes between successive speeders using the probability density function is 0.7981.

Step-by-step explanation:

The  cumulative distribution function of the random variable <em>X, </em>the waiting time, in hours, between successive speeders spotted by a radar unit is:

F(x)=\left \{ {{0;\ x

(a)

Compute the probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function as follows:

12\ \text{minutes}=\frac{12}{60}=0.20\ \text{hours}

The probability is:

P(X

                  =(1-e^{-8x})|_{x=0.20}\\\\=1-e^{-8\times 0.20}\\\\=0.7981

Thus, the probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function is 0.7981.

(b)

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{d F (x)}{dx}=\left \{ {{0;\ x

Compute the probability of waiting less than 12 minutes between successive speeders using the probability density function as follows:

P(X

                  =8\times [\frac{-e^{-8x}}{8}]^{0.20}_{0}\\\\=[-e^{-8x}]^{0.20}_{0}\\\\=(-e^{-8\times 0.20})-(-e^{-8\times 0})\\\\=-0.2019+1\\\\=0.7981

Thus, the probability of waiting less than 12 minutes between successive speeders using the probability density function is 0.7981.

3 0
3 years ago
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