2. A sum of money was deposited on 2 January 2007 in an investment fund which

3/4 + 5/8= ?<br><br><br> ignore this it told me to do atleast 20 words in order to ask a question.

scoray [572]

Answer:

6/8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can anybody help me find the area of this shape?

hjlf

Answer:

18x11 198 + 201 =399 I.D.K

Step-by-step explanation:

6 0

2 years ago

What must be the value of x for a to be parallel to b? m∠1 = 98 and m∠2 = 9x+17

Umnica [9.8K]

I think it is C .....

4 0

3 years ago

Could someone help me arrange these pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (2

Zina [86]

Answer:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

Step-by-step explanation:

Required

Arrange in increasing order of slope

Slope (m) is calculated using:

$m = \frac{y_2 -y_1}{x_2 - x_1}$

So, we have:

(a) (15, 30) and (20, 40)

$m = \frac{40 -30}{20- 15}$

$m = \frac{10}{5}$

$m =2.00$

(b) (12, 32) and (18, 48)

$m = \frac{48 -32}{18- 12}$

$m = \frac{16}{6}$

$m = 2.67$

(c) (27, 12) and (72, 32)

$m = \frac{32-12}{72- 27}$

$m = \frac{20}{45}$

$m = 0.44$

(d) (45, 15) and (60, 20)

$m = \frac{20-15}{60- 45}$

$m = \frac{5}{15}$

$m = 0.33$

(e) (27, 2) and (243, 18)

$m = \frac{18-2}{243- 27}$

$m = \frac{16}{216}$

$m = 0.07$

(f) (18, 63) and (24, 84)

$m = \frac{84-63}{24- 18}$

$m = \frac{21}{6}$

$m = 3.50$

(g) (63, 9) and (84, 12)

$m = \frac{12 -9}{84- 63}$

$m = \frac{3}{21}$

$m = 0.14$

From least to greatest slope, the pair of points are:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

6 0

2 years ago

What are the solutions of the inequality (x-3)(x+5)<=0

GarryVolchara [31]

Assuming that the inequality you were going for was a ≤, set both polynomials less than or equal to 0.

x - 3 ≤ 0

x + 5 ≤ 0

For the first equation add 3 to both sides of the inequality. For the second, subtract 5 from both sides.

x ≤ 3

x ≤ - 5

These would be your solutions I guess, however, if you want to expand upon that, your actual answer is (- ∞, - 5] because if you were to plot these two inequalities on a number line, that is where the overlap would occur.

4 0

2 years ago