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crosses x-axis at (2, 0 ) and y-axis at (0, - 4 )
To find where the graph crosses the x and y axes ( intercepts )
• let x = 0, in the equation for y- intercept
• let y = 0, in the equation for x- intercept
x = 0 : y = 0 - 4 = - 4 ⇒ (0, - 4 )
y = 0 : 2x - 4 = 0 ⇒ 2x = 4 ⇒ x = 2 ⇒ (2, 0 )
Answer:
A
Step-by-step explanation:
Area of Triangle = BH/2
B = 11
Height = 2
11*2 = 22
22/2 = 11
11 sq units = A
Step-by-step explanation:
Take a look at the picture, And tell me if am wrong
B is the answer because if u subtact both x and y
