The low temperatures for a week in Edmonton, Alberta are -15 C, -12 C, -10 C, -12 C, -18 C, -20 C, and -25 C. What is the mean l
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In parallelogram, LMNO,
Because Opposite angles are equal:
Therefore, 2x = 3x -55
Or x= 55
Now, the sum of angles in a parallelogram is 360
2x+3x-55+5y+5y =360
5x +10y -55 = 360
5*55 -55 + 10y = 360
10y +220 = 360
10y = 140
y=14
Thus, x=55 and y= 14
Because Opposite angles are equal:
Therefore, 2x = 3x -55
Or x= 55
Now, the sum of angles in a parallelogram is 360
2x+3x-55+5y+5y =360
5x +10y -55 = 360
5*55 -55 + 10y = 360
10y +220 = 360
10y = 140
y=14
Thus, x=55 and y= 14
The standard form for a parabola is (x - h)2 = 4p (y - k), where the focus is (h, k + p) and the directrix is y = k - p. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix (d)
is x = h - p.
So directrix is: y = k - p and the focus is at:
(h, k+p)
Since our focus is: (1, 3) and directrix is: y = 1,
thus h = 1, k+p = 3, and k-p = 1
Therefore k = 3-p, 3-p-p = 1, k = 3-p = 3-1 = 2
3-2p = 1, -2p = -3+1, -2p = -2, p = 1
Now we plug p, k, & h into standard form:
(x - h)2 = 4p (y - k)
y = 1/4 (x-1)^2 + 2
is x = h - p.
So directrix is: y = k - p and the focus is at:
(h, k+p)
Since our focus is: (1, 3) and directrix is: y = 1,
thus h = 1, k+p = 3, and k-p = 1
Therefore k = 3-p, 3-p-p = 1, k = 3-p = 3-1 = 2
3-2p = 1, -2p = -3+1, -2p = -2, p = 1
Now we plug p, k, & h into standard form:
(x - h)2 = 4p (y - k)
y = 1/4 (x-1)^2 + 2