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3 years ago

Use the number line below. Which fraction is equivalent to

Mathematics

2 answers:

marissa [1.9K]3 years ago

6 0

Which fraction is equivalent to 1/2? Answer:B.

tankabanditka [31]3 years ago

3 0

B easy simplify 3/6 and it’s 1/2 half of 6 is 3 so B is the answer

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A bag contains 7 red, 4 blue, and 6 white marbles.

Leno4ka [110]

Answer:

28/289

Step-by-step explanation:

7 red, 4 blue, and 6 white = 17 marbles

P ( red ) = number of red / total

= 7/17

Replace the marble

7 red, 4 blue, and 6 white = 17 marbles

P ( blue ) = number of blue / total

= 4/17

P (red, replace, blue) = 7/17* 4/17

=28/289

4 0

3 years ago

2(x-3)+5=3(x-1) how to solve?

jasenka [17]

Answer:

2x-12+5=3x-3

1. subtract 3x-2x

-12+5=x-3

2.-12 add to 5

-7=x-3

3. add three to seven

-4=x

Step-by-step explanation:

6 0

3 years ago

G=x-c/x. for x how do yoy make this an equation for x? help

zzz [600]

1.
$\displaystyle \text{if }\quad G=x- \frac{C}{x} \\\\$

$x \neq 0$

Multiply both sides by x:

$\displaystyle Gx=x\bigg(x- \frac{C}{x}\bigg )\\\\Gx=x^2-C$

Subtract from both sides Gx:
$Gx-Gx=x^2-C-Gx\\x^2-Gx-C=0$

Then solve this equation:

$\displaystyle x^2-Gx-C=0\\\\x_{1,2}= \frac{G\pm \sqrt{G^2+4C} }{2}$

2.
$\displaystyle\text{if}\quad G= \frac{x-C}{x}$

$x \neq 0$

Multiply both sides by x:

$Gx=x-C$

Subtract from both sides Gx:

$x-C-Gx=0$

Then solve this equation:

$\displaystyle x-Gx-C=0\\x(1-G)=C\\x= \frac{C}{1-G}$

7 0

3 years ago

A salesperson earns $350.25 per week plus 12% of her weekly sales. Which of the following describes the sales necessary for the

Lynna [10]

Let X describes the sales

350.25+0.12x=800.5
Now solve for x
0.12x=800.5-350.25
0.12x=450.25
X=450.25÷0.12
X=3,752.08

the sales necessary for the salesperson to earn at least $800.50 in one week is 3,752.08

5 0

3 years ago

I need hard and easy math questions with the answer, i need 10 questions thnx

nydimaria [60]

Answer:

https://www.khanacademy.org/

Step-by-step explanation:

I am not entirely sure what you mean however if you sign up for this website and go to whichever grade level you need you can practice all you want

8 0

1 year ago