Look at the gradient of both the equations (the x multiplier, usually known as m), and there are a couple of rules:
Parallel: The gradients are identical
Perpendicular: Look at the gradients as fractions. To get the perpendicular to a gradient you flip the fraction and change the sign. If this is the case for the two gradients, then they are perpendicular.
Answer:
There is no square root of n , if n is negative
Well if i had to make an educated guess my assumption would be similar to the hypothesis of this complicated situation now what i'm trying to say is i have no idea hope you find someone who can help you.
First find the slope of the line segment joining the points.
Slope = ((-5)-7)/(1-(-3)) = -3
The slope of any perpendicular to the line is 1/3
Find the midpoint of the line segment by taking the average of the coordinates.
x-coord of midpoint = (-3+1)/2 = -1
y-coord of midpoint = (7-5)/2 = 1
Midpoint : (-1,1)
Point-slope equation for line of slope 1/3 that passes through (-1,1):
y-1 = (1/3)(x+1)
