Answer:
Step-by-step explanation:
1. There are only 4 numbers including 5 that follow the "five or more" requirment, and the probability of spinning it once is 4/8, or 1/2. (The total sections is 8) Then we multiply 1/2 and 1/2 together to get the "two times in a row" requirement done. (1/2)*(1/2)= 1/4 is the probability.
2. There are two values on the spinner that are a multiple of 3, 3 itself and 6. Again, the total amount of numbers/sections is 8, so the probability of spinning a multiple of three is 2/8 or 1/4. The probability of spinning an odd number is 4/8 or 1/2. (1/2)*(1/4)=1/8 is the probability.
3. The probability of spinning one odd number is 1/2, and so we multiply 1/2 by itself four times. (1/2)*(1/2)*(1/2)*(1/2)=1/16 is the probability.
4. There are 6 numbers greater than two on the number wheel not including two itself. So the probability of that is 6/8, or 3/4. Then we multiply 3/4 by itself 3 times as it asks. (3/4)*(3/4)*(3/4)*(3/4)=81/256 is the probability.
Note that I am not really sure about the answer myself, but I hope that this can help in some way. Good luck! :)
Answer:
12 units
Step-by-step explanation:
The radius is half of the diameter, so we need to double 6 to get 12.
Hey there,
a-7=3(b+2), we do 3 times b and 3 times 2 according to the rule.
a-7=3b+6 we change + to - and - to + when move nums from 1 side to another one.
a=3b+13 we get the solution.
Hope this helps :)
I thing it c
hope you got it right
