Question

Find the length of AH for which MATH is a parallelogram.A. 3B. 4C. 6D. 10

Answer 1

The answer is 3. Would you like me to explain it?

Answer 2

Answer:

Step-by-step explanation:

Alright, lets get started.

For being this quadrilateral to be a parallelogram, the diogonals must be bisected.

It means,

$AP=HP$

$2f-5=5f-17$

taking similar terms together,

$5f-2f=17-5$

$3f=12$

$f=4$

So,

$AP=2f-5=2*4-5=3$

Similarly,

$HP=5f-17=5*4-17=3$

$AH=AP+HP$

$AH=3+3=6$

AH = 6               :   Answer

Hope it will help :)