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sasho [114]
3 years ago
14

What is the interest for a principal of $3,500 at a simple annual interest rate of

Mathematics
2 answers:
anygoal [31]3 years ago
7 0

Answer:

$70

Step-by-step explanation:

$3500*(2%/100%) = $70

It pretty simple just take 2% and times it by the principle if it's only for one year.

Zarrin [17]3 years ago
6 0
I’m pretty sure it’s 80.5 I’m not sure though
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A six-sided dice is rolled twice. Find the probability that the larger of the two rolls was equal to 5.
Diano4ka-milaya [45]

The probability that the larger of the two rolls was equal to 5 is; 2/9

<h3>Probability of possible outcomes</h3>

The total number of possible outcomes when the dice is rolled twice is 36 outcomes.

Now, for the larger of the two rolls to equal 5, the total number of favourable  outcomes are 8 which are;

(1, 5), (2, 5), (3, 5), (4, 5), (5, 1), (5, 2), (5, 3), (5,4)

Thus, probability that the larger of the two rolls was equal to 5 is;

P(larger of 2 rolls equals 5) = 8/36 = 2/9

Read more about probability of possible outcomes at; brainly.com/question/19916581

8 0
2 years ago
If 3(x - 4) = x + 4, then x =8
Greeley [361]

Answer:

Valid

Step-by-step explanation:

3(x-4)=x+4              <em>Given</em>

3x-12=x+4                <em>Distribute</em>

2x=16<em>                      Subtract x from both sides and add 12 to both sides</em>

x=8                           <em>Divide each side by 2.</em>

<em>  </em>

<em />

6 0
3 years ago
Please solve<br>x^2+6x+5=0​
Inessa [10]

Answer:

plus the other number and the other one

8 0
3 years ago
How can I divide 5.19 and 16.8
soldi70 [24.7K]
5.19 / 16.8 = <span>0.30892857142</span>
4 0
4 years ago
Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form
ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

\frac{n!}{n1!*n2!*...*nk!}

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

\frac{10!}{2!*2!*2!*2!*2!}=113,400

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

\frac{10!}{2!*2!*3!*3!}=25,200

So, If each team has either two or three students, The number of ways  form teams are:

113,400 + 25,200 = 138,600

6 0
3 years ago
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