Answer:
cjdfnadjffseufhwuouefvnj
Step-by-step explanation:
(i) U' = Φ
(ii) A∩A' = Φ
(iii) A – ( B U C) = {5,7,9}
(iv) A' U ( B U C ) = {2,4,6,8,10}
(v) A' U ( B' ∩ C') = {2,4,5,6,7,8,9,10}
0.33
Given the following :
P(speeding) = p(s) = 0.75
P(being stopped) = p(t)
P(speeding and gets stopped) = p(s n t) = 0.25
Find the probability that he is stopped, given that he is speeding is written as P(t | s) ;
P(t | s) = p(s n t) / p(s)
P(s n t) = 0.25
P(s) = 0.75
Hence,
P(t | s) = 0.25 / 0.75
P(t | s) = 0.33
4*3
12
12*6
72
hope it help
f(x)=(x-2)(x+2)(x-4)
