Answer:
Step-by-step explanation:
I've already done this question for you. You must be reposting it because the answer was not correct according to the way the computer was programmed to get the answer. I can only think that you don't count the interface between the cube and the larger figure at all. So let's do it that way.
Start with the cube.
The formal equation is Area = 5 * s^2
It has 5 equal sides each one measuring 3 * 3
Area = 5 * 3^2 = 45
Now go to the other figure
The front and back face measure 14*6*2 = 168
Left and Right Sides are 2 * 6 * 8 96
Top and Bottom 2 * 14 *8 224
Don't count the base of the cube at all so subtract 3*3 -9
Total 524
If that does not work, please leave a note at the bottom of this question.
Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
Answer:
Check the explanation
Step-by-step explanation:
Kindly check the attached image for the step by step solution to the question
Answer:
17.10
Step-by-step explanation:
