Need help on this one too!!
1 answer:
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Step-by-step explanation:
Hey there!
Follow the steps to get answer.
- Use one point formula and find 1st equation.
- After that you find the slope of second equation.
- Use the condition of perpendicular lines and find the slope of first equation.
- Put slope value of equation in equation (i) and simplify them to get equation.
The equation of a line passing through point (2,3) is;
(y-3)= m1(x-2).......(i).
Another equation is;
2nd equation..
Now, From equation (ii)
We have;
Comparing equation (ii) with y = mx+c.
We get;
Slope = -1/2.
For perpendicular lines,
Therefore the slope is 2.
Put value of slope (m1) in equation (i). We get;
Simplify them to get equation.
Therefore the required equation is y = 2x-1.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
The initial number of horses = 24
year = 2011
Coordinates (2011, 24)
when the number of horses became 32, year was 2014
Coordinates (2014, 32)
We find the slope = rate of change
slope = change in number of horses/change in number of years
slope = (32-24)/(2014-2011)
slope = 8/3
The point slope formula:
The number of horses in year 2020
using points: (2011, 24) and (2020, y), we equate with the slope since it is constant for any two points on this model.
8/3 = (y - 24)/(2020 - 2011)
8/3 = (y - 24)/9
cross multiply:
8(9) = 3(y - 24)
72 = 3y - 72
72 + 72 = 3y
144 = 3y
144/3 = 3y/3
y = 48
Hence, there will be 48horses in 2020 (option A)