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inn [45]
3 years ago
10

Please answer! (Easy) Will give brainlist!

Mathematics
1 answer:
EastWind [94]3 years ago
4 0
What do i have to answer?
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What is the probability that a student who plays an instrument is in band
m_a_m_a [10]

Answer:

20/25

Step-by-step explanation:

Here, we want to calculate the probability that a student who plays an instrument is in band

The number of students who play instruments are;

25

Amongst this,

20 are in a band

So the probability of having a student who plays instrument and is in a band will be;

20/25 = 4/5

3 0
3 years ago
If B is the midpoint of AC and AC=8x-20 find BC
Elza [17]

We know that AC=8x-20 and B is the mid-point of AC

⇒ AB = BC = \frac{AC}{2}

⇒ BC = \frac{8x-20}{2}

⇒ BC = 4x-10


3 0
3 years ago
Read 2 more answers
Evaluate f(x)=3(2)x for x=−1.
Tcecarenko [31]

Replace x with -1

F(-1) = 3(2)(-1) =

3 times 2 times -1 = -6

The answer is -6

8 0
4 years ago
PLEASE HELP!! Will give Brainliest!!!
Vesna [10]

Answer:

6.99

Step-by-step explanation:

4.3+1.7=6

41.94/6=6.99

3 0
4 years ago
Read 2 more answers
The number of bacteria in a refrigerated food product is given by N ( T ) = 27 T 2 − 180 T + 100 N(T)=27T2-180T+100, 7 < T &l
NeX [460]

Answer:

N(T(t))=432t^2-374.4t-118.88

The number of Bactria after 5.8 hours is 12242.

Step-by-step explanation:

The number of bacteria in a refrigerated food product is given by

N(T)=27T^2-180T+100

where, T is the temperature of the food.

When the food is removed from the refrigerator, then the temperature is given by

T(t)=4t+1.6

We need to find the composite function N(T(t)).

N(T(t))=N(4t+1.6)

N(T(t))=27(4t+1.6)^2-180(4t+1.6)+100

N(T(t))=432t^2+345.6t+69.12-720t-288+100

N(T(t))=432t^2-374.4t-118.88

where N(T(t)) is the number of bacteria after t hours.

Substitute t=5.8 in the above function.

N(T(5.8))=432(5.8)^2-374.4(5.8)-118.88

N(T(5.8))=14532.48-2290.4

N(T(5.8))=12242.08

N(T(5.8))\approx 12242

Therefore, the number of Bactria after 5.8 hours is 12242.

7 0
4 years ago
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