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san4es73 [151]
3 years ago
10

Almost done just need to get to 80

Mathematics
2 answers:
Vilka [71]3 years ago
8 0

Answer:

60%

Step-by-step explanation:

6/10 of the shape is green, meaning that it is 60 %.

taurus [48]3 years ago
6 0

Answer:

60%

Step-by-step explanation:

count the squares.

count the green.

6/10 = 60%

You might be interested in
Is it true that energy never moves
seraphim [82]

Answer:

False

Step-by-step explanation:

Energy is transferred from one object to another when a reaction takes place. Energy comes in many forms and can be transferred from one object to another as heat, light, or motion, to name a few.

7 0
4 years ago
a) What is an alternating series? An alternating series is a whose terms are__________ . (b) Under what conditions does an alter
andriy [413]

Answer:

a) An alternating series is a whose terms are alternately positive and negative

b) An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|, converges if 0< b_{n+1} \leq b_n for all n, and \lim_{n \to \infty} b_n = 0

c) The error involved in using the partial sum sn as an approximation to the total sum s is the remainder Rn = s − sn and the size of the error is bn + 1

Step-by-step explanation:

<em>Part a</em>

An Alternating series is an infinite series given on these three possible general forms given by:

\sum_{n=0}^{\infty} (-1)^{n} b_n

\sum_{n=0}^{\infty} (-1)^{n+1} b_n

\sum_{n=0}^{\infty} (-1)^{n-1} b_n

For all a_n >0, \forall n

The initial counter can be n=0 or n =1. Based on the pattern of the series the signs of the general terms alternately positive and negative.

<em>Part b</em>

An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|  converges if 0< b_{n+1} \leq b_n for all n and \lim_{n \to \infty} b_n =0

Is necessary that limit when n tends to infinity for the nth term of bn converges to 0, because this is one of two conditions in order to an alternate series converges, the two conditions are given by the following theorem:

<em>Theorem (Alternating series test)</em>

If a sequence of positive terms {bn} is monotonically decreasing and

<em>\lim_{n \to \infty} b_n = 0<em>, then the alternating series \sum (-1)^{n-1} b_n converges if:</em></em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

then <em>\sum_{n=1}^{\infty}(-1)^{n-1} b_n  converges</em>

<em>Proof</em>

For this proof we just need to consider the sum for a subsequence of even partial sums. We will see that the subsequence is monotonically increasing. And by the monotonic sequence theorem the limit for this subsquence when we approach to infinity is a defined term, let's say, s. So then the we have a bound and then

|s_n -s| < \epsilon for all n, and that implies that the series converges to a value, s.

And this complete the proof.

<em>Part c</em>

An important term is the partial sum of a series and that is defined as the sum of the first n terms in the series

By definition the Remainder of a Series is The difference between the nth partial sum and the sum of a series, on this form:

Rn = s - sn

Where s_n represent the partial sum for the series and s the total for the sum.

Is important to notice that the size of the error is at most b_{n+1} by the following theorem:

<em>Theorem (Alternating series sum estimation)</em>

<em>If  \sum (-1)^{n-1} b_n  is the sum of an alternating series that satisfies</em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

Then then \mid s - s_n \mid \leq b_{n+1}

<em>Proof</em>

In the proof of the alternating series test, and we analyze the subsequence, s we will notice that are monotonically decreasing. So then based on this the sequence of partial sums sn oscillates around s so that the sum s always lies between any  two consecutive partial sums sn and sn+1.

\mid{s -s_n} \mid \leq \mid{s_{n+1} -s_n}\mid = b_{n+1}

And this complete the proof.

5 0
4 years ago
To help consumers assess the risks they are​ taking, the Food and Drug Administration​ (FDA) publishes the amount of nicotine fo
Blizzard [7]

Answer:

t=\frac{26.8-29.9}{\frac{2.7}{\sqrt{9}}}=-3.44    

df=n-1=9-1=8  

p_v =P(t_{(8)}  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and is not enough evidence to conclude that the claim is true.

Step-by-step explanation:

Data given

\bar X=26.8 represent the sample mean

s=2.7 represent the sample standard deviation

n=9 sample size  

\mu_o =29.9 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean exceed 29.9 or no, the system of hypothesis would be:  

Null hypothesis:\mu \geq 29.9  

Alternative hypothesis:\mu < 29.9  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{26.8-29.9}{\frac{2.7}{\sqrt{9}}}=-3.44    

P-value

The degrees of freedom are given by:  

df=n-1=9-1=8  

Since is a one sided test the p value would be:  

p_v =P(t_{(8)}  

Conclusion  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and is not enough evidence to conclude that the claim is true.

6 0
4 years ago
Solve the question for the letter r: d=rt
topjm [15]
So we are just solving for R?

     d = rt
   d/t = rt/t
   d/t = r

Simply isolate the r to one side, using the principle "what you do to one side, you must do to the other." 
 
ANSWER: r = d/t 
                       ( d divided by t)

Hope this helps!! God bless! :)
3 0
3 years ago
Due today pls helppppp
LiRa [457]
<h3>Answer:   19.1</h3>

====================================================

Work Shown:

tan(angle) = opposite/adjacent

tan(C) = AB/BC

tan(theta) = x/BC

tan(23) = (8.1)/BC

BC*tan(23) = 8.1

BC = (8.1)/tan(23)

BC =  19.0824041631723

BC = 19.1

In this case, rounding to 3 sig figs means we round to the nearest tenth.

Make sure your calculator is in degree mode.

3 0
3 years ago
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