Answer:
filter the data
Explanation:
its like when you filter a search on y o u t u b e and say u search among us u can filter and say live vids or channel's
Answer:
#include <iostream>
#include <stack>
#include <queue>
#include <string>
int main()
{
while ( true )
{
std::string letters;
std::cout << "Please enter a word (Enter - exit): ";
std::getline( std::cin, letters );
if ( letters.empty() ) break;
std::stack<char>
s( std::stack<char>::container_type( letters.begin(), letters.end() ) );
std::queue<char>
q( std::queue<char>::container_type( letters.begin(), letters.end() ) );
while ( !s.empty() && s.top() == q.front() )
{
s.pop();
q.pop();
}
if ( s.empty() ) std::cout << "The word is a palindrome" << std::endl;
else std::cout << "The word is not a palindrome" << std::endl;
}
return 0;
}
Explanation:
A <em>stack</em> is used to replicate a stack data structure in C++ while <em>Queue </em>container is a replica of the queue data structure in C++, Unlike stack, in the queue container, there are two ends, i.e. front, and back.
In the code above to be able to use used stack and queue, we included the headers #include <stack> and#include <queue>.
Time management,they wouldn’t have enough time to read it and they would become more stressed out
Answer:
These are the supplies in the list:
[‘pencil’, ‘notebook’, ‘backpack’, ‘pen’, ‘calculator’]
Explanation:
The line return (\n) character will be in the output (so there will be a change of line), but it will NOT be visible as it would have been interpreted as a special character.
So the output will be on 2 different lines, with no \n visible.
If the command would have been: print('These are the supplies in the list:\n', supplies), with single quotes (') instead of double quotes (") then then \n would have been printed but not interpreted as a special character. At least in most computer language. Since we don't know of which language the question refers to, we can't be sure at 100%.