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Kruka [31]
3 years ago
5

5x times 1509y what is the answer

Mathematics
1 answer:
alisha [4.7K]3 years ago
5 0

Answer:

7545xy

Step-by-step explanation:

i hope this helps

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Jemer lost his ball and decided to buy a new one. the new ball cost $300. which is three times the price of his old ball. how mu
shusha [124]

Answer:

The cost of the old ball was $100.

Step-by-step explanation:

The cost of the new ball = $300

The new ball has three times the price of his old ball.

So, let the price of the old ball be = x

As per situation, we get the equation:

3x=300

Dividing both sides by 3:

\frac{3x}{3}= \frac{300}{3}

=> x = 100

Hence, the cost of the old ball was $100.

8 0
3 years ago
How do you find the fraction of 0.35
SOVA2 [1]

Answer:

\frac{7}{20}

Step-by-step explanation:

0.35 is the same as 35/100

which can be simplified to 7/20

4 0
3 years ago
Evaluate the line integral c y3 ds,<br> c.x = t3, y = t, 0 ≤ t ≤ 3
Temka [501]
\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\int_{t=0}^{t=3}t^3\sqrt{1^2+(3t^2)^2}\,\mathrm dt=\int_0^3t^3\sqrt{1+9t^4}\,\mathrm dt

Take u=1+9t^4 so that \mathrm du=36t^3\,\mathrm dt. Then

\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}
7 0
3 years ago
At a bake sale, as student spent $11.00 buying 3 brownies and 5 cookies. His friend spent $3.95 buying 1 brownie and 2 cookies.
dybincka [34]

Answer:

$2.25

Step-by-step explanation:

Let "b" be the price of 1 brownie and "c" the price of 1 cookie.

At a bake sale, a student spent $11.00 buying 3 brownies and 5 cookies. Symbolicaly,

3 b + 5 c = 11.00   [1]

His friend spent $3.95 buying 1 brownie and 2 cookies. Symbolicaly,

1 b + 2 c = 3.95

b = 3.95 - 2c   [2]

If we replace [2] in [1], we get

3 (3.95 - 2c) + 5 c = 11.00

11.85 - 6c + 5c = 11.00

c = 0.85

If we replace c = 0.85 in [2], we get

b = 3.95 - 2 (0.85) = 2.25

8 0
3 years ago
Write 44/3 as a whole or mixed number in simplest form.
stealth61 [152]
14 2/3 is the answer
7 0
3 years ago
Read 2 more answers
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