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2 years ago

What is x in the problem x divided by (-2)=-3

Mathematics

1 answer:

larisa [96]2 years ago

3 0

Answer:

x =6

Step-by-step explanation:

x / -2 = -3

Multiply each side by -2

-2* x/-2 = -3 * -2

x = 6

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pishuonlain [190]

Answer:

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Step-by-step explanation:

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2 years ago

Find the slope of a line that passes through points (-1,-5) and (6,9).

Nana76 [90]

Answer:

${ \rm{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }} \\ \\ { \rm{slope = \frac{9 - ( - 5)}{6 - ( - 1)} }} \\ \\ { \rm{slope = \frac{14}{7} }} \\ \\ { \boxed{ \rm{ \: \: slope = 2 \: \: }}}$

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2 years ago

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What is the sum of 5x^2y and (2xy^2 + x^2y)

eimsori [14]

Recognize that you must combine "like" terms. 5x^2y and x^2y are "like" terms.

Adding them together, you get 6x^2y.

Now add 2xy^2 to 6x^2y. These are NOT "like" terms, so you end up with
6x^2y+2xy^2 as your final answer. This answer is acceptable as is.

However, you could factor out the common factors: 2xy(3x+y).

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2 years ago

Factorize completely the following algebra expression :<br>81x^4-16y^8

ohaa [14]

Here’s your answer the A/= it means the answer is okay.

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2 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago