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NARA [144]
3 years ago
15

As a salesperson, you are paid $50 per week plus $3 per sale. This week you want your pay to be at least $110. What is the minim

um number of sales you must make to earn at least $110?
Mathematics
2 answers:
alexgriva [62]3 years ago
7 0
110 (goal) - 50 (base pay) = 60 (pay from sales only)

60 (total pay from sales) / 3 (cost per individual sale) = 20 (qty of sales)
Paul [167]3 years ago
6 0
3s+50=|110
           |-50
      <u>3</u>s= <u>60</u>
      3      3
        s =20

Therefore the salesperson will need 20 sales.
You might be interested in
rectangle A has a length of 24 meters and a width of 20 meters. rectangle B has the same area as rectangle A. the width of recta
blagie [28]
To solve this, first we'll find the area of the rectangle A,

Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A

now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B

finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m



7 0
3 years ago
Juanita can complete 12 math problems in 40 minutes. How many problems can she complete in 60 minutes
RSB [31]

Answer:

The answer is 18.

Step-by-step explanation:

3 0
3 years ago
Write an expression that is equivalent to (3x-2)-x^2+2x+5), combing like terms
ss7ja [257]

Answer:

-x^2+5x+3

Step-by-step explanation:

Remove unnecessary parenthesis.

3x-2-x^2+2x+5

Collect like terms.

5x+3-x^2

Use the commutative property to reorder the terms.

-x^2+5x+3

4 0
3 years ago
Audrey drew a model to determine how many eighths are in 5.
____ [38]

Answer:

there are 40 eighths in 5

Step-by-step explanation:

40/8 (the fraction)

40÷8=5

is that what the question is asking?

8 0
3 years ago
Read 2 more answers
Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

5 0
3 years ago
Read 2 more answers
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