I'm assuming you don't still need these? Sorry I didn't see this in time
Answer:
k=0
Step-by-step explanation:
3k+6-3=3
3k = 3+3-6
3k = 6-6
3k = 0
k = 0
We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
Answer:
convert the expression for N into logs
evaluate those logs using a log table
thus determine log N
calculate antilog of log N
Thus,
log
N
=
(
647
⋅
32
×
0.00000147
8.473
×
64
)
=
log
(
647
⋅
32
)
+
log
(
0.00000147
)
−
log
(
8.473
)
−
log
(
64
)
Answer: 1 2/3 more
Step-by-step explanation:
