Answer:
We conclude that a function is defined as having only one corresponding y-value for each x-value.
Hence, option (C) is true.
Step-by-step explanation:
We know that A function is a certain relationship is defined as having only one corresponding y-value for each x-value.
Considering the function
Here,
- x is the input and f(x) or y is the output.
- 'x' is often called an independent value and y is called the 'dependent' value.
Considering the table
x y
1 2
2 3
3 4
4 5
The values in the table satisfy the function y = x+1.
It is clear from the table that the function has only one corresponding y-value for each x-value. In other words, there is no repetition of 'x' value.
Therefore, we conclude that a function is defined as having only one corresponding y-value for each x-value.
Hence, option (C) is true.
Answer:
It is MOST LIKELY NOT going to land on green.
Step-by-step explanation:
Since the spinner has 6 sides, the total possible outcome is 6. There are 3 reds, 2 blues and 1 green.
The probability that the spinner will land on a green is 
. But since we are looking for the probability that it won't land on green, we have 
From here we can best describe the likelihood that the spinner will land on a colour not green as: it is MOST LIKELY NOT going to land on green
Answer:
7.28 miles
Step-by-step explanation:
Suppose the distance at closest approach is represented by x. Then the distance to the point of closest approach at the first sighting is ...
d1 = x·tan(62°)
At the second sighting, the distance to the point of closest approach is ...
d2 = x·tan(38°)
The difference of these distances is 8 miles, so we have ...
d1 -d2 = 8 = x(tan(62°) -tan(38°))
Dividing by the coefficient of x, we find ...
x = 8/(tan(62°) -tan(38°)) ≈ 7.2764 . . . . miles
The point of closest approach is about 7.28 miles from the landmark.
Answer:
Maybe if you give a better quality photo that isn't sideways! :D
Step-by-step explanation:
Answer:
by the question
statement. reason
1.<ABD=<ADB. given
2<CBD=<CDB. given
3 <ABD +<CBD=. adding statement 1
<ADB+<CDB. and second
4.<ABC=<ADC. by whole part axiom
