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3 years ago

Point A is at (-1,-9) and Point B is at (2,4). What is the midpoint of line segment AB

Mathematics

2 answers:

spin [16.1K]3 years ago

7 0

Answer:

The answer to your question is (1/2, -5/2)

Step-by-step explanation:

Data

A = (-1, -9)

B = (2, 4)

Formula of midpoint

Xm = (x1 + x2) / 2

Ym = (y1 + y2)/2

x1 = -1 y1 = -9 x2 = 2 y2 = 4

To solve this problem just substitute the values in the formula and simplify.

Xm = (-1 + 2) / 2

Ym = (-9 + 4) / 2

-Simplify

Xm = 1/2

Ym = -5/2

-Solution

Midpoint (1/2, -5/2)

Mkey [24]3 years ago

6 0

Answer:

Midpoint( .5,-2.5)

Step-by-step explanation:

To find the midpoint, add the x coordinates and divide by 2 and then add the y coordinates and divide by 2

x: (-1+2)/2 = 1/2=.5

y: (-9+4)/2 = -5/2 = -2.5

Midpoint( .5,-2.5)

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Find the value of x for which 2x ^(1/ 2) = 32.

Mrac [35]

Answer:

The value of x will be 8

Step-by-step explanation:

We have given that $2\sqrt{x}=32$

We have to find the value of x

As $2\sqrt{x}=32$

For finding the value of x we have to square both side

On squaring both side

We done squaring both side for easy simplification

$4x=32$

So x = 8

So the value of x will be 8

So answer will be 8

5 0

3 years ago

An opaque cylindrical tank with an open top has a diameter of 3.25 m and is completely filled with water. When the afternoon Sun

kicyunya [14]

Answer:

10.69

Step-by-step explanation:

We must first know that the angle of refraction is given by the following equation:

n_water * sin (A_water) = n_air * sin (A_air)

where n is the refractive index, for water it is 1.33 and for air it is 1.

The angle (A) in the air is 22.8 °, and that of the water is unknown.

Replacing these values we have to:

1.33 * sin (A_water) = 1 * 0.387

sin (A_water) = 1 * 0.387 / 1.33

A_water = arc sin (0.2907) = 16.9 °

now for the tank depth:

h = D / tan (A_water)

D = 3.25

Replacing

h = 3.25 / tan 16.9 °

h = 10.69

Therefore the depth is 10.69 meters.

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2 years ago

Determine if there is a proportional relationship between the two quantities

Shalnov [3]

Answer:

The table a not represent a proportional relationship between the two quantities

The table b represent a proportional relationship between the two quantities

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

Verify each table

Table a

Let

A ----> the independent variable or input value

B ----> the dependent variable or output value

the value of k will be

$k=\frac{B}{A}$

For A=35, B=92 ---> $k=\frac{92}{35}=2.63$

For A=23, B=80 ---> $k=\frac{80}{23}=3.48$

the values of k are different

therefore

There is no proportional relationship between the two quantities

Table b

Let

C ----> the independent variable or input value

D ----> the dependent variable or output value

the value of k will be

$k=\frac{D}{C}$

For C=20, D=8 ---> $k=\frac{8}{20}=0.40$

For C=12.5, D=5 ---> $k=\frac{5}{12.5}=0.40$

the values of k are equal

therefore

There is a proportional relationship between the two quantities

The linear equation is equal to

$D=0.40C$

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2 years ago

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tia_tia [17]

Answer:

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3 years ago

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Helen [10]

Answer:

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Step-by-step explanation:

5 0

2 years ago

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