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lys-0071 [83]
2 years ago
6

The ratio of men to women working for a company is 8 to 5. If there are 234 employees total, how many women work for the company

?
Mathematics
2 answers:
Aloiza [94]2 years ago
7 0

Answer:

87 men

145 women

Step-by-step explanation:

8 to 5

8x+5x=234

8x=234

x=234/8

x=~29

3*29=87 men

5*29=145 women

Dimas [21]2 years ago
3 0

Answer:

144

Step-by-step explanation:

The ratio of men to women working for a company is 8 to 5.

Total men and women working as per the ratio is 8+5 = 13

So the ratio of men to total  is  

the ratio of women to total  is  

there are 234 employees total

To find the number of men works , we make a proportion

Cross multiply it

8 * 234 = 13x

1872 = 13x

Divide by 13 on both sides

x= 144

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Given the true/false statements are true (facts), select the best logical induction made from thoses statements: Mo likes orange
bekas [8.4K]

Answer:

People like oranges

Step-by-step explanation:

Given:

Mo likes oranges. Jai likes oranges. Ben likes oranges.

We have a few different options;

Option A: People don't like other fruit, such as apples. This can't be possible because we have only been given people who like oranges.

Option B: People on like oranges. This can't be possible because only is the case where people do not like any fruit except oranges, and we are not sure of this.

Option C: People like oranges. This can be possible because Mo, Jai, and Ben likes oranges

Option D: People like fruit. This can't be possible because we are not sure if people like all fruits or not

6 0
3 years ago
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x4 ln(x) (a) Find the interval on which f is incre
Ainat [17]

Answer: (a) Interval where f is increasing: (0.78,+∞);

Interval where f is decreasing: (0,0.78);

(b) Local minimum: (0.78, - 0.09)

(c) Inflection point: (0.56,-0.06)

Interval concave up: (0.56,+∞)

Interval concave down: (0,0.56)

Step-by-step explanation:

(a) To determine the interval where function f is increasing or decreasing, first derive the function:

f'(x) = \frac{d}{dx}[x^{4}ln(x)]

Using the product rule of derivative, which is: [u(x).v(x)]' = u'(x)v(x) + u(x).v'(x),

you have:

f'(x) = 4x^{3}ln(x) + x_{4}.\frac{1}{x}

f'(x) = 4x^{3}ln(x) + x^{3}

f'(x) = x^{3}[4ln(x) + 1]

Now, find the critical points: f'(x) = 0

x^{3}[4ln(x) + 1] = 0

x^{3} = 0

x = 0

and

4ln(x) + 1 = 0

ln(x) = \frac{-1}{4}

x = e^{\frac{-1}{4} }

x = 0.78

To determine the interval where f(x) is positive (increasing) or negative (decreasing), evaluate the function at each interval:

interval                 x-value                      f'(x)                       result

0<x<0.78                 0.5                 f'(0.5) = -0.22            decreasing

x>0.78                       1                         f'(1) = 1                  increasing

With the table, it can be concluded that in the interval (0,0.78) the function is decreasing while in the interval (0.78, +∞), f is increasing.

Note: As it is a natural logarithm function, there are no negative x-values.

(b) A extremum point (maximum or minimum) is found where f is defined and f' changes signs. In this case:

  • Between 0 and 0.78, the function decreases and at point and it is defined at point 0.78;
  • After 0.78, it increase (has a change of sign) and f is also defined;

Then, x=0.78 is a point of minimum and its y-value is:

f(x) = x^{4}ln(x)

f(0.78) = 0.78^{4}ln(0.78)

f(0.78) = - 0.092

The point of <u>minimum</u> is (0.78, - 0.092)

(c) To determine the inflection point (IP), calculate the second derivative of the function and solve for x:

f"(x) = \frac{d^{2}}{dx^{2}} [x^{3}[4ln(x) + 1]]

f"(x) = 3x^{2}[4ln(x) + 1] + 4x^{2}

f"(x) = x^{2}[12ln(x) + 7]

x^{2}[12ln(x) + 7] = 0

x^{2} = 0\\x = 0

and

12ln(x) + 7 = 0\\ln(x) = \frac{-7}{12} \\x = e^{\frac{-7}{12} }\\x = 0.56

Substituing x in the function:

f(x) = x^{4}ln(x)

f(0.56) = 0.56^{4} ln(0.56)

f(0.56) = - 0.06

The <u>inflection point</u> will be: (0.56, - 0.06)

In a function, the concave is down when f"(x) < 0 and up when f"(x) > 0, adn knowing that the critical points for that derivative are 0 and 0.56:

f"(x) =  x^{2}[12ln(x) + 7]

f"(0.1) = 0.1^{2}[12ln(0.1)+7]

f"(0.1) = - 0.21, i.e. <u>Concave</u> is <u>DOWN.</u>

f"(0.7) = 0.7^{2}[12ln(0.7)+7]

f"(0.7) = + 1.33, i.e. <u>Concave</u> is <u>UP.</u>

4 0
3 years ago
What is the value of x?
lesantik [10]
50.6
\frac{x}{72.6 }  =  \frac{46.2 - 14}{46.2}
x = 32.2 \times 72.6  \div 46.2
x = 50.6


8 0
3 years ago
Ella's grandmother sewed her a change purse. When she gifted it to her, Ella counted 23 coins already in it. Ella noticed there
juin [17]
The answer to this problem is 17dimes
5 0
3 years ago
Read 2 more answers
What is the answer to |x-4|&lt;13
VARVARA [1.3K]

Answer:

<h2>The solution is -9 < x < 17.</h2>

Step-by-step explanation:

|x-4|<13.

The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.

Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.

7 0
3 years ago
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