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2 years ago

9

A baker sells bread for $6 a loaf and rolls for $2 each. The baker needs to sell $66 worth of baked goods by

1 answer:

Ulleksa [173]2 years ago

8 0

Answer:

the answer is 9

Step-by-step explanation:

the baker already sold 6 rolls $(6*9)+ (2*6)=66$ $54+12=66$

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The width of a deck is 5 feet shorter than its length. The equation that represents this situation is y = x – 5. What does x rep

ollegr [7]

X represents the length of a deck. There are three parts to this equations. The 1. width, 2. the length, and 3. the 5 feet shorter. Using the key words, y = the width of a deck (uses the term is which means =) So that takes the width part out of the equation. Then, 5 feet shorter means -5 than a number. That takes away the 5 feet shorter part of the equation. That leaves x to equal the length of the deck.

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3 years ago

What are the 2 square roots of 0.0625

Fofino [41]

0.03125 and 0.015625

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3 years ago

Do question 4 and explain how you got the answer please. The question is on the image

daser333 [38]

Step 1: Subtract 50 from both sides.
<span><span><span>y+50</span>−50</span>=<span>200−50</span></span><span>y=150
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3 years ago

Read 2 more answers

Write each phrase as an algebraic expression.<br> 16 seconds faster than Aya’s time.

Anna35 [415]

Given:

The given phrase is 16 seconds faster than Aya’s time.

To find:

The algebraic expression for the given phrase.

Solution:

Let x be the Aya’s time.

16 seconds faster than Aya’s time. It means 16 seconds less than Aya’s time.

We know that a negative sign "-" is used for less than.

16 seconds less than Aya’s time = $x-16$

16 seconds faster than Aya’s time = $x-16$

Therefore, the required algebraic expression is $x-16$ .

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3 years ago

Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

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$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for d<em>y</em>/d<em>x</em> :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

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If <em>y</em> ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

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3 years ago