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navik [9.2K]
2 years ago
9

A baker sells bread for $6 a loaf and rolls for $2 each. The baker needs to sell $66 worth of baked goods by

Mathematics
1 answer:
Ulleksa [173]2 years ago
8 0

Answer:

the answer is 9

Step-by-step explanation:

the baker already sold 6 rolls (6*9)+ (2*6)=66                  54+12=66                                                                              

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3 divided by 4 is 3/4 what is 1/4 of 3
Zigmanuir [339]

Answer:

0.75 or 3/4

Step-by-step explanation:

1/4 of 3 would still end up to be 3/4 or as a decimal it would be .75

7 0
3 years ago
The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
Firdavs [7]

Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy

The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0
3 years ago
What is the slope of a line whose graph is parallel to the graph of -3x+y=2?
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Step-by-step explanation:

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Nadusha1986 [10]

Answer:

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Step-by-step explanation:

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