Answer:
rjogir
grggreijgojrejow
g
Step-by-step explanation:
C is the correct answer I had this question before
x = # of ham sandwiches
14-x = # of turkey sandwiches ( as Lexi made 14 sandwiches)
as the question said that the number of ha sandwiches are 4 less than twice number of turkey sandwiches,
x = 2 * (14-x) - 4 = 24 - 2x
3x=24
x = 8
the number of ham sandwiches is 8, and the number of turkey sandwiches is 14-8=6
Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e. 
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
