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Anna71 [15]
3 years ago
7

A healthy human heart beats about 1,533,000 times a year. A sparrow's heart beats about 2,417,760,000 times in a year. About how

many times faster does the sparrow's heart beat compared to the human heart? Show your work.
Mathematics
1 answer:
Allisa [31]3 years ago
6 0

Answer: 1577.14

Step-by-step explanation:

From the question, we are informed that a healthy human heart beats about 1,533,000 times a year and that a sparrow's heart beats about 2,417,760,000 times in a year.

To calculate how many times faster the sparrow's heart beat compared to the human heart, we divide the sparrow's heartbeat in a year by the humans heartbeat in a year. This will be:

= 2,417,760,000 / 1,533,000

= 1577.14 times

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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
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keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

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\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

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Step-by-step explanation:

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3 years ago
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