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3 years ago

Help me please it says that I need help !!

Mathematics

1 answer:

nataly862011 [7]3 years ago

5 0

Answer:

A, D

Step-by-step explanation:

The independent variable is plotted on the x-axis. It is labeled "number of cans". The dependent variable is plotted on the y-axis. It is labeled "number of tennis balls". Then each ordered pair is ...

(independent variable, dependent variable) = (cans, balls)

Then the point (2, 6) corresponds to (2 cans, 6 balls).

The applicable descriptive statements are ...

A. 2 cans contain 6 tennis balls

D. There are 6 tennis balls in 2 cans

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Solve the triangle for all missing sides, rounded to the nearest tenth, and angles, rounded to the nearest degree.

evablogger [386]

Answer:

x=32 y=416 M<ABC=158°

Step-by-step explanation:

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3 years ago

An analyst tested the null hypothesis µ ≥ 30 against the alternative hypothesis that µ < 30. The analyst reported a p-value o

hoa [83]

Answer:

For significance levels lower than 0.07, the null hypothesis would be rejected.

Step-by-step explanation:

Decision regarding the null hypothesis:

The decision depends on the p-value of the test.

If the p-value of the test is less than the significance level, the null hypothesis is reject.

If the p-value of the test is more than the significance level, the null hypothesis is not reject.

The analyst reported a p-value of 0.07. For what significance level of will the null hypothesis would be rejected?

From the theory above, for significance levels lower than 0.07, the null hypothesis would be rejected.

8 0

3 years ago

Plzzz help its a math question

Step2247 [10]

Ur answer is -4......

7 0

3 years ago

Read 2 more answers

Tracy needs to find the length and width of the equiptment storage room where she works. the room is 2 meters long than it is wi

ElenaW [278]

Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
So 4W = 24 -4 =20
W = 20/4= 5, L = 5+2= 7

Double check
24 = 2*(5+7) = 2 *12 = 24

4 0

3 years ago

Read 2 more answers

(10 points)Assume IQs of adults in a certain country are normally distributed with mean 100 and SD 15. Suppose a president, vice

vesna_86 [32]

Answer:

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Step-by-step explanation:

To solve this question, we need to use the binomial and the normal probability distributions.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability the president will have an IQ of at least 107.5

IQs of adults in a certain country are normally distributed with mean 100 and SD 15, which means that $\mu = 100, \sigma = 15$

This probability is 1 subtracted by the p-value of Z when X = 107.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{107.5 - 100}{15}$

$Z = 0.5$

$Z = 0.5$ has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 probability that the president will have an IQ of at least 107.5.

Probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

First, we find the probability of a single person having an IQ of at least 130, which is 1 subtracted by the p-value of Z when X = 130. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{130 - 100}{15}$

$Z = 2$

$Z = 2$ has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

Now, we find the probability of at least one person, from a set of 2, having an IQ of at least 130, which is found using the binomial distribution, with p = 0.0228 and n = 2, and we want:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.9772)^{2}.(0.0228)^{0} = 0.9549$

$P(X \geq 1) = 1 - P(X = 0) = 0.0451$

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

What is the probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130?

0.3085 probability that the president will have an IQ of at least 107.5.

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Independent events, so we multiply the probabilities.

0.3082*0.0451 = 0.0139

8 0

3 years ago