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zepelin [54]
3 years ago
11

Solve the following system equation graphically on the set of axes below y= x+4 and y= -3/2 - 1 PLEASE HELP MEEE

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

y=4

y= -1

Step-by-step explanation:

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80 times 30 plus 60 equals
UNO [17]

Answer:

2460

Step-by-step explanation:

Hope this helps :)

6 0
3 years ago
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Does the point (0,4) make either equations y=-2x and y=x+3 true? Explain.
Nikolay [14]

Answer:

Neither

Step-by-step explanation:

To verify, we substitute the values in the equations:

y = -2x\\y = -2 \times 0\\y = 0

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

y = x+3\\y= 0+3\\y = 3

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

5 0
3 years ago
What is the value of x?
Fittoniya [83]
Let the 2 equal lengths be represented by 2p.  Then you can write the equation of ratios

  p       2p
---- = -------
16      x+4

which simplifies to 

  1        2
----- = ------
 16      x+4

then x+4 = 32, and x = 28 (answer)
8 0
3 years ago
99 + 81 = 9(11 help eeeeeeeeeeeeeeee
Leokris [45]

Answer:

180?

Step-by-step explanation:

3 0
2 years ago
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Someone help me please
galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }

Hence, ∛27 = 27^{(\frac{1}{3})}

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

3 0
3 years ago
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