Solve the following system equation graphically on the set of axes below y= x+4 and y= -3/2

Solve the inequality for x.<br> 7x-26<-5(2-3x)

Masja [62]

Answer:

$x > 2$

Step-by-step explanation:

7x-26<-5(2-3x)

first write out the equation

7x-26<-10 +15x

then solve the -5(2-3x)

by multiplying -5 by 2 and -5 by 3x which will give the answer -10 and 15x

7x-15x<-10+26

Now put the numbers with X first and since we moved the (+15x) into the otherside we change its sign to (-15x)

and because we put the (-26) into the otherside we do the same thing and change it into (+26)

-8x<16

Now we combine the same numbers so 7x-15x and -10+26

Next we divide both sides by (-8)

so (-8x÷-8) and (16÷-8)

and because we divided with a negative number (-8)

and we have an inequality( < ) we flip the sign from smaller than to greater than.

and so the final answer is x>2

or x is greater than 2

7 0

3 years ago

PLS HELP!! GIVING BRAINLIEST TO FIRST CORRECT ANSWER!!+50 POINTS

Elena-2011 [213]

Answer(s):

154 in²
3168/7 km²
38.5 m²

Revising the area of a circle formula

We already know that the area of a circle is expressed as $\pi r^{2}$ .

The "r" variable is known as the radius.

<h2><u>Solving each problem given:</u></h2><h3>Solving Problem 4:</h3>

We are given the radius of circle, which is 7 in. Let us substitute the radius in the formula. Once substituted, we can simplify the expression obtained to determine the area of the circle shown in the picture.

$\implies \pi (7)^{2}$

$\implies \huge\text{(}\dfrac{22}{7} \huge\text{)}(7)^{2}$ <em> </em>

$\implies \huge\text{(}\dfrac{22}{7} \huge\text{)}(7)(7)$

$\implies (22)(7)$

$\implies 154 \ \text{in}^{2}$

<h3>Solving Problem 5:</h3>

In this problem, we are given the diameter to be 24 kilometers. Since the radius of the circle is half the diameter, we can tell that the radius of the circle is 24/2 kilometers, which is 12 kilometers.

$\implies \pi (12)^{2}$

$\implies \huge\text{(}\dfrac{22}{7}\huge\text{)} (12)^{2}$

$\implies \huge\text{(}\dfrac{22}{7}\huge\text{)} (12)(12)$

$\implies \dfrac{3168}{7} \ \text{km}^{2}$

<h3>Solving Problem 6:</h3>

We are given the radius of circle, which is 3.5 in. Let us substitute the radius in the formula. Once substituted, we can simplify the expression obtained to determine the area of the circle shown in the picture.

$\implies \pi (3.5)^{2}$

$\implies \huge\text{(}\dfrac{22}{7}\huge\text{)} (3.5)^{2}$

$\implies \huge\text{(}\dfrac{22}{7}\huge\text{)} (3.5)(3.5)$

$\implies \huge\text{(}\dfrac{22}{2}\huge\text{)} (3.5) = (11) (3.5)$

$\implies 38.5 \ \text{m}^{2}$

Note: <em>The radius given in this problem was not clearly stated. If the radius I stated here, is incorrect, please notify me in the comments. Thanks!</em>

Learn more about area of circles: brainly.com/question/12414551

3 0

3 years ago

Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,

Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is $\dfrac{1}{6} = 0.1667$ .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is $\dfrac{1}{6}$ .

Numbers on the dice (X) P(X)

+1 $\frac{1}{6}$

+2 $\frac{1}{6}$

+3 $\frac{1}{6}$

-4 $\frac{1}{6}$

+5 $\frac{1}{6}$

-6 $\frac{1}{6}$

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X) = $\sum X \times P(X)$

= $(+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}$