Factor the denominator:
(3x-1)(x+2)
every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.
since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.
the answer here is C.
Answer:
1. x= 8
2. x= 6
3. x= 7
4. x= -8
Code: BECI
Step-by-step explanation:
Those two numbers are 30 and 12.
30+12=42
and
30*12=360
:P
FG : (3,7)(-4,-5)
slope = (-5 - 7) / (-4-3) = -12/-7 = 12/7
y = mx + b
slope(m) = 12/7
(3,7)...x = 3 and y = 7
now we sub, we r looking for b, the y int
7 = 12/7(3) + b
7 = 36/7 + b
7- 36/7 = b
49/7 - 36/7 = b
13/7 = b
so ur equation is : y = 12/7 + 13/7.....slope = 12/7, y int = 13/7
HI : (-1,0)(4,6)
slope = (6 - 0) / (4 - (-1) = 6/5
no need to go any farther.....these lines have different slopes...and their not negative reciprocals....so there will be one solution. Answer is : neither.
Answer:
the answer for this question 1200
Step-by-step explanation:
