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The formula that is useful for solving both of these problems is ...
9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
9514 1404 393
Answer:
- 4/13 h ≈ 0.308 h
- 22 9/13 km ≈ 22.7 km
Step-by-step explanation:
Mary and Amaruk are starting 35 -15 = 20 km apart. Their closing speed is 40 +25 = 65 km/h. The time it will take to close the gap between them is ...
t = (20 km)/(65 km/h) = 20/65 h = 4/13 h ≈ 0.308 h
They will pass each other after 4/13 hours, about 18 minutes 28 seconds.
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In that time, Mary will have increased her distance from Hall Beach by ...
d = (4/13 h)(25 km/h) = 100/13 km = 7 9/13 km
Her distance from Hall Beach when she passes Amaruk will be ...
15 km + 7 9/13 km = 22 9/13 km ≈ 22.7 km . . . . . distance from Hall Beach
