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sashaice [31]
2 years ago
5

What is the meaning of annuity​

Mathematics
2 answers:
ankoles [38]2 years ago
7 0
An annuity is a type of retirement income product that you buy with some or all of your pension pot. It pays a regular retirement income either for life or for a set period. Annuities – the basics. Higher income for medical conditions or unhealthy lifestyle. Your other retirement income options.
Goryan [66]2 years ago
4 0

Answer:

a fixed sum of money paid to someone each year, typically for the rest of their life.

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What is the answer to this question? Please help!
maks197457 [2]

Answer:

B

Step-by-step explanation:

-3\sqrt{2}+3\sqrt{8}= \\\\-3\sqrt{2}+3\sqrt{2\cdot 2^2}= \\\\-3\sqrt{2}+6\sqrt{2}= \\\\3\sqrt{2}

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Choose the law and the formula that would be used to solve the triangle.
Oksana_A [137]

Answer: A^2

Step-by-step explanation:

Angle C + Angle B = Angle A

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The gas tank in dad’s car holds 12 gallons. The gas tank in mom’s truck holds 50% more than that. How much gas does the truck’s
Lady_Fox [76]

Answer:To calculate this you just have to calculate a rule of three with both gas tanks, so if the dad´s car holds 12 gallons of gas, and the mom´s car holds 50% more that means 150% of in the rule of three: So the total amount of gallons that the mom´s car tank can hold is 18 gallons.

Step-by-step explanation:Please make me brainliest please

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A school trip to the zoo costs $36, which includes $8 for the bus ticket and cost for 2 passes. Both passes cost the same amount
elena55 [62]

14$ because you subtract 8 - 36 = 28 then divide 28 by 2 and get 14

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Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w
siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$  is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4} $

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0
2 years ago
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