What is please answer 8 to -6

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago

What is the result when 2/5x + 1 1/4 is subtracted 2/38x - 4 1/9? (NEED ASAP)

Katyanochek1 [597]

Answer:

33 x/ 95 − 103/ 36

Step-by-step explanation: i had too many steps and i cant type them all out.

This answer is only correct if you are talking about subtracting.

7 0

3 years ago

Write an equation of the line that passes through the points (2,−1) and (0,1).

Alina [70]

0,1 is the y-intercept

5 0

4 years ago

Read 2 more answers

Find the value of each expression. Show your work.

Verdich [7]

Answer:

$A) (1.2)^{2} = 1.44$

$B)2^ 3+17-(3\times 4) = 13$

$C)\frac{(9)^2}{(3)^3} = 3$

Step-by-step explanation:

Here, the given expressions are:

A) $(1.2)^{2}$

Solving this, we get

$(1.2)^{2} = 1.2 \times 1.2 = 1.44$

⇒ $(1.2)^{2} = 1.44$

B) $2^ 3+17-(3\times 4)$

Now, solving this, we get

$2^ 3+17-(3\times 4) = (2 \times 2 \times2) + (17 -12)\\=8 + 5 = 13$

⇒ $2^ 3+17-(3\times 4) = 13$

C) $\frac{(9)^2}{(3)^3}$

Simplifying this, we get

$\frac{(9)^2}{(3)^3} = \frac{(9\times9)}{(3 \times 3\times3)} = 3$

⇒ $\frac{(9)^2}{(3)^3} = 3$

4 0

3 years ago

Lydia's mom earns $4 in rewards for every $75 she spends at the grocery store. If she earned $44 in rewards last month, how much

8_murik_8 [283]

Answer:

$495

Step-by-step explanation:

Take baseline amount of 75 dollars and divide it by 4. This will get you to the answer 11.25. Use 11.25 and multiply it by what she received in rewards. 11.25 times 44 equals....495!

6 0

3 years ago