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Setler [38]
4 years ago
13

Help i don't understand ​

Mathematics
2 answers:
Rus_ich [418]4 years ago
8 0
The shape rotated 90 degrees to the left
Murljashka [212]4 years ago
5 0
The transformation is : rotation because the two figures have the same measures
You might be interested in
The blue dot is at what value on the number line? -10 -4
Alisiya [41]

Answer:

The blue dot is at the value of -19

Step-by-step explanation:

There is a gap of 3 between each space

 -19    -16   -13    -10   -7    -4

5 0
3 years ago
Help, WILL GIVE BRAINLIEST
Harlamova29_29 [7]

Answer:

A= 14 B=17 C=20 D=26

Step-by-step explanation:

Not 100% sure this is what you needed but this is my try.

6 0
3 years ago
Make up an equation of the form y = kx +b, the graph of which passes through the following points: A (8, –1) and B (–4, 17)
igor_vitrenko [27]

Answer:

One equation would be y= -1.5x +11

Step-by-step explanation:

Here's a table to show the coordinates

x:             y:

8              -1

-------------------

-4             17

the x coor. 8  goes down by 12 to get to the next x coor. -4.

8-12= -4

the y coor. -1 goes up by 18 to get to the next y coor. 17.

-1+18= 17

therefore 18/-12 is -1.5 which can be your k in y=kx+b.

Check your answer.

-1.5*8= -12 but when you add 11, you get the y coor. -1

Do the same with the other x coor.

-4*-1.5= 6 + 11 =17

11 can be your b in the slope-intercept form equation.

One equation may be y = -1.5x +11

4 0
3 years ago
Find the equivalent expression using the same basis (34•84)^3
vichka [17]

Answer:

(2)^9•(3)^3•(7)^3•(17)^3

Step-by-step explanation:

(34•84)^3

=(34)^3•(84)^3

=(2•17)^3•(2•2•3•7)^3

=(2)^3•(17)^3•(2)^3•(2)^3•(3)^3•(7)^3

=(2)^(3+3+3)•(17)^3•(3)^3•(7)^3

=(2)^9•(3)^3•(7)^3•(17)^3

7 0
3 years ago
Read 2 more answers
HELP ME QUICK: Suppose AB has one endpoint at A(0, 0). If (5, 3) is the midpoint of AB, what are the coordinates of point B?
DiKsa [7]

Answer:

<h3>           B(10, 6)</h3>

Step-by-step explanation:

If P is midpoint of AB and:  A(0,\,0)\,,\quad P(5,\,3)\,,\quad B(x_B,\,y_B)

then:

x_P-x_A=x_B - x_P\qquad\quad\ \wedge\qquad y_P-y_A=y_B - y_P\\\\ 5-0=x_B-5\qquad\quad\wedge\qquad 3-0=y_B -3\\\\ x_B=5+5\qquad\qquad\wedge\qquad\ \ y_B=3+3 \\\\ {}\quad x_B=10\qquad\qquad\wedge\qquad\qquad \ y_B=6

5 0
3 years ago
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