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olga55 [171]
3 years ago
14

When N divided by 5 leaves a remainder of 2, find the one's digit of N

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

Step-by-step explanation:

If the number ends in 0 or 5 those are the only two results that 5 will divide into a number evenly.

For example 105/5 = 21

And example 1020/5 = 204

So if you want a  remainder of 2, there are 2 ways to get it.

1) If the number ends in a two, you will get a remainder of 2. That's because 0 + 2 will give 2.

For example 252 / 5 = 50 with a remainder of 2

2) The other way is if the end number is 7.

3347 / 5 = 669 with a remainder of 2.

The reason this works is if you subtract 2 from the number given then the units digit will be either 0 or 5. Those two endings result in even division.

Alexus [3.1K]3 years ago
3 0

Step-by-step explanation:

One's digit of N can be 2 or 7.

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Derive the equation of the parabola with a focus at (2, 4) and a directrix of y = 8. f(x) = −one eighth (x − 2)2 + 6 f(x) = one
vfiekz [6]

Answer:

A

Step-by-step explanation:

For any point (x, y ) on the parabola the focus and directrix are equidistant

Using the distance formula

\sqrt{(x-2)^2+(y-4)^2} = | y - 8 |

Squaring both sides gives

(x - 2)² + (y - 4)² = (y - 8)²

(x - 2)² + y² - 8y + 16 = y² - 16y + 64 ( rearrange and simplify )

(x - 2)² = - 8y + 48

8y = - (x - 2)² + 48

y = - \frac{1}{8}(x - 2)² + 6 → A


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-57 + 57 I really need the answer
3241004551 [841]

Answer:

The answer is 0

Step-by-step explanation:

-57 cancels out 57 making it 0.

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A jar contains 17 orange, 7 pink, and 4 black marbles. A marble is drawn at random. What is the probability that the marble is p
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Cynthia Besch wants to buy a rug for a room that is 21 ft wide and 34 ft long. She wants to leave
Daniel [21]

Answer:

Dimensions of the rug = 13 ft × 26 ft

Step-by-step explanation:

Dimensions of the room = 21 ft × 34 ft

Area of the room = 21 × 34 = 714 ft²

Cynthia wants to leave a uniform strip of floor around the rug.

Let the width of the rug = x ft

Then the dimensions of the rug will be = (21- 2x)ft × (34 - 2x)ft

Area of the rug = (21 - 2x)×(34 - 2x) square feet

338 = (21 - 2x)×(34 - 2x)

338 = 714 - 68x - 42x + 4x²

4x² - 110x + 714 - 338 = 0

4x² - 110x + 376 = 0

2x² - 55x + 188 = 0

2x² - 47x - 8x + 188 = 0

x(2x - 47) - 8(x - 47) = 0  

(x - 4)(2x - 47) = 0

x = 4, \frac{47}{2}

For x = 23.5 area of the rug will be negative.

Therefore, x = 4 ft will be the width of the rug.

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