7 towels to how many blankets

Rocky pays a flat rate of $5 per month plus $0.10 per minute for

PSYCHO15rus [73]

For his total monthly bill to be under a twenty dollars he could make a 149 calls
20-5=15
15/.10=150
150-1=149
15-.10=14.9
14.9+5=19.9
So the maximum number of calls he can make is 149 a month

6 0

3 years ago

Which of the following charts can be used to determine the cumulative probability that several sources contribute to a problem?

Svetllana [295]

Answer: a. Pareto

Step-by-step explanation:

A Pareto Chart is a graph that indicates the frequency of defects, as well as their cumulative impact. Pareto Charts are useful to find the defects to prioritize in order to observe the greatest overall improvement.

Fishbone diagram or Ishikawa diagram is a cause-and-effect diagram that helps managers to track down the reasons for imperfections, variations, defects, or failures.

Ordered Histogram is an approximate representation of the distribution of numerical data.

A histogram is a bar graph that illustrates the frequency of an event occurring using the height of the bar as an indicator.

7 0

3 years ago

The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are

STALIN [3.7K]

Answer:

We conclude that the proportion of dropouts has changed from the historical value of 0.081.

Step-by-step explanation:

We are given that in 2009, the high school dropout rate was 8.1%. A polling company recently took a survey of 1000 people between the ages of 16 and 24 and found 6.5% of them are high school dropouts.

The polling company would like to determine whether the proportion of dropouts has changed from the historical value of 0.081.

Let p = proportion of school dropouts rate

SO, Null Hypothesis, $H_0$ : p = 0.081 {means that the proportion of dropouts has not changed from the historical value of 0.081}

Alternate Hypothesis, $H_A$ : p $\neq$ 0.081 {means that the proportion of dropouts has changed from the historical value of 0.081}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of high school dropout rate = 6.5%

n = sample of people = 1000

So, test statistics = $\frac{0.065-0.081}{{\sqrt{\frac{0.065(1-0.065)}{1000} } } } }$

= -2.05

Also, P-value is given by the following formula;

P-value = P(Z < -2.05) = 1 - P(Z $\leq$ 2.05)

= 1 - 0.97982 = 0.0202 or 2.02%

Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the proportion of dropouts has changed from the historical value of 0.081.

7 0

4 years ago

A fisherman yanks a fish vertically out of the water with an acceleration of 2.5! !! using very light fishing line that has a br

Artyom0805 [142]

Two forces act on the fish, and these are:

1) Its weight mg, downwards and

2) pressure in the string, T, upwards which is 22 N when the string breaks.
In the result of these two forces, the fish had an acceleration of 2.5 m/s^2 in the upward way.

So, T - mg = m*2.5

=> m = T / (2.5 + g)

=> m > 22 / (2.5 + 9.8) ( when the string snaps )

=> m > 1.79 kg.

As a result, the mass of the fish is more than 1.79 kg as the line has been broken.

6 0

3 years ago

This is a coached example

spayn [35]

The top is 329 x 26=m

5 0

4 years ago