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uranmaximum [27]
3 years ago
5

Function for g whose graph is similar to f(x)=3x^2 shifted right 6 units and upward 5 units

Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0

f(x) = 3 {x}^{2}

function g has to be the transformation of function f. Therefore,

g(x) = 3 {(x - 6)}^{2}  + 5

is the answer.

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Zach is 3 years older than twice his sister Maya’s age.
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The answer is z=2m+3 so the first one is right
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Simplify 4x(3x-7)-19x^2)-19x^2
Sedbober [7]
The answer for this problem is
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Which products result in a perfect square trinomial? Check all that apply.
sladkih [1.3K]

The <em><u>correct answers</u></em> are:

B=(xy + x)(xy + x) ; C=(2x – 3)(–3 + 2x) ; and E=(4y² + 25)(25 + 4y²)

Explanation:

In order to have a perfect square trinomial, we must multiply two binomials that are exactly the same.  For (xy+x)(xy+x), are multiplying two identical binomials.

For (2x-3)(-3+2x), we are multiplying two binomials that are the same but written in a different order.  The same is true of (4y² + 25)(25 + 4y²).

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B12x-7%3D0%20%5C%5C" id="TexFormula1" title="2x^{2} +12x-7=0 \\" alt="2x^{2}
m_a_m_a [10]

Answer:

-2. 46

- 9.54

Step-by-step explanation:

  • 2x²+12x-7=0
  • 2x²+12x+18= 25
  • 2*(x²+6x+9)=25
  • 2*(x+6)²= 5²
  • x+6= 5√2/2 ⇒ x= 5√2/2 -6 ≈ -2. 46
  • x+6= -5√2/2 ⇒ x= -5√2/2 -6 ≈ - 9.54
4 0
2 years ago
A random sample of 28 statistics tutorials was selected from the past 5years and the percentage of students absent from each one
Vesna [10]

Using the t-distribution, the 90% confidence interval for the mean number of absences is given by: (9.22, 11.60).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 90% confidence interval, with 28 - 1 = 27 df, is t = 1.7033.

Researching this problem on the internet, the parameters are given by:

\overline{x} = 10.41, s = 3.71, n = 28.

Hence the bounds of the interval are given by:

  • \overline{x} - t\frac{s}{\sqrt{n}} = 10.41 - 1.7033\frac{3.71}{\sqrt{28}} = 9.22
  • \overline{x} + t\frac{s}{\sqrt{n}} = 10.41 + 1.7033\frac{3.71}{\sqrt{28}} = 11.60

The 90% confidence interval for the mean number of absences is given by: (9.22, 11.60).

More can be learned about the t-distribution at brainly.com/question/16162795

#SPJ1

8 0
2 years ago
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