Which of the following slopes of a line passes through points (2, 3) and (4.7)? 5 2 3

Mathematics

1 answer:

Mumz [18]3 years ago

8 0

Answer: 2

Step-by-step explanation:

7-3/4-2 = 4/2 = 2

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Can someone help me with this Geometry problem, please?

Doss [256]

Hello from MrBillDoesMath!

Answer:

Discussion:

Total Surface area = area of pyramid base + 4 ( area of triangular face)

In our case this becomes

4*4 + 4( (1/2) (4)(7) ) =

= 16 + (2)(4)(7)

= 16 + 56

= 72

which is the first choice.

Note: the area of a triangular face was computed using (1/2) b h, which in our case is

(1/2) (4) (7)

Thank you,

MrB

3 0

3 years ago

Solve and graph the compound inequalities. (You don’t need to graph it on a line plot but if you could that would be great!)

lidiya [134]

Part A

$-12 < 5x - 2 < 13\\\\-12+2 < 5x - 2+2 < 13+2 \ \text{ ... add 2 to all sides}\\\\-10 < 5x < 15\\\\-10/5 < 5x/5 < 15/5 \ \text{ ... divide all sides by 5 to isolate x}\\\\-2 < x < 3\\\\$

To graph this, we plot open holes at -2 and 3 on the number line. Shade between these open holes to represent values between -2 and 3, but we don't include the endpoints.

See figure 1 below.

===============================================

Part B

Solve the first inequality to get

$3x < -9\\\\3x/3 < -9/3\\\\x < -3\\\\$

Now solve the second inequality

$2x \ge x+1\\\\2x-x \ge x+1-x\\\\x \ge 1\\\\$

We have $x < -3 \ \text{ or } \ x \ge 1$

The graph will have an open hole at -3 and a closed/filled in circle at 1. We shade everywhere but the region between these marked values. The left portion in blue represents stuff smaller than -3; the right portion in red represents values equal to 1 or larger.

See figure 2 below.