4 is a solution of x < -5 true or false -3 is a solution of y

Swedish researchers concluded that viewing and discussing art soothes the soul and helps relieve medical conditions such as high

zavuch27 [327]

Answer:

i) Assigning women at random ensures that the two groups are comparable.

iv) A control group provides a baseline for comparisons to determine treatment effects.

Step-by-step explanation:

(a)

It is pertinent that there two comparable groups. In light of the fact that it will help in making better decisions since there will be some people who have blood pressure as a result of uncontrolled physical characteristics such as anger, positive attitude, lower blood pressure. etc Thus, there is a need to consider two equivalent groups.

(b)

A control group is used as a benchmark for determining the cause and effect of a treatment on a given experimental group. This may be in regard to the social aspect of meeting other individuals involved that make up the physical changes.

4 0

3 years ago

The surface area of a rectangular prism is increased by a factor of 16.

Natali5045456 [20]

Answer:

64

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.

Juli2301 [7.4K]

Answer:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

$\hat p=\frac{97}{110}=0.882$ estimated proportion of students who completed the modules before class

$p_o=0.8$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%: Null hypothesis:[tex]p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

5 0

4 years ago

Distributive property of 224÷7

Tcecarenko [31]

224
-----

=1/7 (224)

=1/7(210 + 14)

=210 14
----- + ------
7 7

= 32

3 0

4 years ago

Renee’s monthly cell phone bill depends on the number of minutes she uses the phone. Renee kept a record of her monthly bills in

natita [175]

Answer:

ok

Step-by-step explanation:

5 0

3 years ago

4 is a solution of x < -5 true or false -3 is a solution of y > -2 true or false