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2 years ago

Please help me with this!!

Mathematics

1 answer:

zubka84 [21]2 years ago

3 0

Step-by-step explanation:

84+36=120ans..........

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First answer = brainliest

nataly862011 [7]

Answer:

120 cubic cm

Step-by-step explanation:

5 0

2 years ago

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Molly opened a bank account. She deposited $86.50 into her account every month for 20 months. She used $24.50 every month to pay

anastassius [24]

She spent $310 on the singing camp.

MY WORK:

I multiplied $86.50*20 because $86.50 is the amount she deposited for 20 months. $86.50*20=$1740.00

Then I multiplied $24.50*20 because she spent $24.50 for 20 months. $24.50*20= $490.00

Then I subtracted $1740.00-$490.00 because she spent $490 out of her bank account. $1740.00-$490.00=$1240.00

Finally, because its 1/4 of her money, I divided $1240.00 by 4. $1240 divided by 4= $310

Hope this helps!!

8 0

3 years ago

What is the interquartile range of the data set? {18, 17, 10, 25, 20, 20, 30, 18, 18, 30, 25} Enter the answer in the box. PLEAS

sasho [114]

The interquartile is 21

7 0

2 years ago

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What else would need to be congruent to show that ABC = PQR by sss

Katen [24]

Ab=pq
qr= bc
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7 0

3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago