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hammer [34]
3 years ago
11

How many solutions does the system have? 6x-y=-1 6x+y=-1

Mathematics
1 answer:
vitfil [10]3 years ago
5 0
This system only have one solution to the problem that is asked
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What is the sign of the product (-5)(-3)(-8)(-6)? (5 points) Positive, because the products (-5)(-3) and (-8)(-6) are negative,
Hatshy [7]
<h3>Answer: Choice B</h3>

Positive, because the products (-5)(-3) and (-8)(-6) are positive, and the product of two positive numbers is positive

=======================================================

Explanation:

Recall we have these rules

  • positive times positive = positive
  • positive times negative = negative
  • negative times negative = positive

Here is one example for each rule

  • 8*7 = 56
  • 5*(-9) = -45
  • -2*(-4) = 8

So based on that, we know that (-5)(-3) is positive. The two negatives cancel each other out so to speak. The same goes for (-8)(-6). Then multiplying any two positive numbers produces another positive outcome.

4 0
2 years ago
I need to know what to do and the answer
Anni [7]

You would take 180•15% to get 27 then you would subtract 180-27 to get 153. After you do the first you would do 200•20% to get 40 200-40=160 so the cheaper one would be the 180 because about 15% discount it’s 153 and 160>153
5 0
3 years ago
A boy spent 2/5 of his money on sweets and 1/3 on pen.​ What fraction of his money did he have remaining?
Anettt [7]

Answer:

2/5 *3/3= 6/15

1/3*5/5= 5/15

6/15+5/15=11/15

4/15 remaining

5 0
3 years ago
Anybody know the integration for this... The answer is k=3
yanalaym [24]
You know that y^2=4x so x=\dfrac{y^2}{4}.
Area of a shaded region is:

$A=\int\limits_0^k\dfrac{y^2}{4}\,dy=\frac{1}{4}\int\limits_0^ky^2\,dy=\frac{1}{4}\left[\frac{y^3}{3}\right]_0^k=\frac{1}{4}\left[\frac{k^3}{3}-\frac{0^3}{3}\right]=\frac{1}{4}\cdot\dfrac{k^3}{3}=\boxed{\frac{k^3}{12}}

so k:

\dfrac{k^3}{12}=\dfrac{9}{4}\\\\\\k^3=\dfrac{9\cdot12}{4}\\\\\\k^3=9\cdot3\\\\k^3=3^3\quad|\sqrt[3]{(\ldots)}\\\\\boxed{k=3}


3 0
4 years ago
A survey was taken of 2000 voters before an election.1650 of the ones surveyed said they would vote for candidate A.What percent
antiseptic1488 [7]
Total of 2000 voters......1650 said they would vote for candidate A

the percent who voted for candidate A is : 1650/2000 = 0.825
multiply that by 100 to get ur percent....0.825 * 100 = 82.5% <==
6 0
3 years ago
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