Of 240 stamps that Harry and his sister collected, Harry collected 3 times as many as his sister. How many did each collected.
1 answer:
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<u><em>Note:</em></u>
<em>Your question is a little unclear. But, from my understanding, I assume you may be asking the evaluation of the expression 36x - y when x = 3 and y = -6.</em>
<em>so I will solve based on my assumption which anyways would clear your concept.</em>
Answer:
The value of 36x - y when x = 3 and y = -6 will be: 114
Step-by-step explanation:
Given
Assuming the expression
36x - y
To Determine
Evaluate 36x - y when x = 3 and y = -6
Given the expression
substitute x = 3 and y = -6 to evaluate the expression
Therefore, the value of 36x - y when x = 3 and y = -6 will be: 114
<u>Answer:</u>
<em>Mathew invested</em><em> $600 and $2400</em><em> in each account.</em>
<u>Solution:</u>
From question, the total amount invested by Mathew is $3000. Let p = $3000.
Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’
So, the amount invested in second account = 3000 – P
Step 1:
Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest earned in first account for one year,
Where
p = amount invested in first account
n = number of years
r = rate of interest
hence, by using above equation we get as,
----- eqn 1
Step 2:
Mathew has paid 8% interest in second account. Let us calculate the simple interest earned in second account,
Step 3:
Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)
Step 4:
Total simple interest = simple interest on first account + simple interest on second account.
Hence we get,
By substituting eqn 1 , 2, 3 in eqn 4
12000=3P + 24000 - 8P
5P = 12000
P = 2400
Thus, the value of the variable ‘P’ is 2400
Hence, the amount invested in first account = p = 2400
The amount invested in second account = 3000 – p = 3000 – 2400 = 600
Hence, Mathew invested $600 and $2400 in each account.