1.
"The spending limit on John’s credit card is given by the function f(x)=15,000+1.5x"
means that if the monthly income of John is $ 5,000 ,he can spend at most
f(5,000)=15,000+1.5*5,000=15,000+ 7,500=22, 500 (dollars)
Or for example
if Johns monthly income is $8,000, then he can spend at most
f(8,000)=15,000+1.5*8,000=15,000+ 12,000=27,000 (dollars)
2.
Now, assume that the maximum amount that John can spend is y.
Then, y=15,000+1.5x
we can express x, the monthly income, in terms of y by isolating x:
y=15,000+1.5x
1.5x = y-15,000
X=y-15,000/1.5
thus, in functional notation, x, the monthly income, is a function , say g, of variable y, the max amount:
X=g(y) y-15000/1.5
since we generally use the letter x for the variable of a function, we write g again as:
G (x) x-15000/1.5
tells us that if the maximum amount that John can spend is 50,000 $, then his monthly income is 23,333 $.
3.
If John's limit is $60,000, his monthly income is
G(600,000)=60,000-15,000/ 1.5=45,000/1.5 =30,000
dollars.
Answer: $ 30,000
Remark: g is called the inverse function of f, since it undoes what f does.
instead of g(x), we could use the notation
Answer:
The length of the segment AB is 18.8 cm or 1.88 dm
Step-by-step explanation:
<u><em>The question in English is</em></u>
Points A, B and C are collinear in this order. Find the length of the segment: a) AB, if AC = 20 cm, BC = 0.12 dm
we have that
----> by Addition segment postulate
substitute the given values in centimeters
Remember that
so
solve for AB
Convert to dm
therefore
The length of the segment AB is 18.8 cm or 1.88 dm
Answer:
the answer is 798 + 789 mawdgghhji the same time as the work of the Maroons
Answer:
2^40.
Step-by-step explanation:
(4^4)^5
= 4^(4*5)
= 4^20
= (2^2)^20
= 2^40.
Answer:
Therefore, the conclusion is valid.
The required diagram is shown below:
Step-by-step explanation:
Consider the provided statement.
Premises: All good students are good readers. Some math students are good students.
Conclusion: Some math students are good readers.
It is given that All good students are good readers, that means all good students are the subset of good readers.
Now, it is given that some math students are good students, that means there exist some math student who are good students as well as good reader.
Therefore, the conclusion is valid.
The required diagram is shown below:
