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avanturin [10]
3 years ago
10

Please help will give brainliest to right answer!!!

Chemistry
1 answer:
Blababa [14]3 years ago
3 0

Answer: 0.28 M HCI

Explanation:

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Answer:

=6.2x10^{-3}mol CuSO_4

Explanation:

Hello,

By developing the following stoichiometric relationship, the required amount could be found as follows:

- Moles of CuSO_4:

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{1mol CuSO_4}{1mol CuSO_4.5H_2O} =6.2x10^{-3}mol CuSO_4

- Grams of CuSO_4

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{1mol CuSO_4}{1mol CuSO_4.5H_2O}*\frac{159.5g CuSO_4}{1mol CuSO_4} =0.989 g CuSO_4

- Moles of water:

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{5mol H_2O}{1mol CuSO_4.5H_2O}=0.031mol H_2O

Finally, one could see that the mass of the anhydrous compound is less than the pentahydrated compound since it is waterless.

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