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liq [111]
4 years ago
10

A sample of sugar (C12H22O11) contains

Chemistry
1 answer:
Mariana [72]4 years ago
3 0

Answer:

0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N =  number of particles

Nᵃ = Avogadros constant = 6.02 x \\10^{23

So, n= \frac{1.505 X 10^{23} }{6.02 X 10^{23}}

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

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