Round to the nearest ten. Look at the ones value, it is a 0. Because 0 is less than 5, round down
913610 rounded to the nearest ten is 913610
hope this helps
According to Vieta's formula, if

are solutions of quadratic equation

, then:

In our case:
The point (8,2,9) is in the first octant.
The closest distance from the coordinate planes is the value y=2, which will therefore be the maximum radius of the required sphere.
The standard equation of a sphere with radius r and centre (u,v,w) is given by
(x-u)^2+(y-v)^2+(z-w)^2=r^2
Substituting r=2, u=8, v=2, w=9, we get the equation of the required sphere
(x-8)^2+(y-2)^2+(w-9)^2=2^2
Question:
A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.
Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling a number greater than 2.
If there is more than one element in the set, separate them with commas.
Answer:


Step-by-step explanation:
Given
A roll of a 6 sided number cube
Solving (a): The sample space
This implies that we list out all number on the number cube.
So:

Solving (b): Outcomes greater than 2
This implies that we list out all number on the number cube greater than 2 i.e. 3 to 6.
So:

The word “of” automatically mean multiplication. So start by making 7 3/4 into an improper fraction: 31/4. Then multiple 3/4 by 31/4. You should get 93/20, or 4 13/20.