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choli [55]
3 years ago
13

Find an equation of the largest sphere with center (8, 2, 9) that is contained in the first octant.

Mathematics
1 answer:
Furkat [3]3 years ago
8 0
The point (8,2,9) is in the first octant.
The closest distance from the coordinate planes is the value y=2, which will therefore be the maximum radius of the required sphere.

The standard equation of a sphere with radius r and centre (u,v,w) is given by
(x-u)^2+(y-v)^2+(z-w)^2=r^2

Substituting r=2, u=8, v=2, w=9, we get the equation of the required sphere
(x-8)^2+(y-2)^2+(w-9)^2=2^2
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Answer:

D) y=14

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Read 2 more answers
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yanalaym [24]

Answer:

19.  C

20.  D

21.  B

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3 years ago
Please help it’s for Alex
nasty-shy [4]
Okay so the y is in absolute value, which means the number could be a negative and the absolute value would make is a positive.
since the sign is greater than, with no equal to underneath it, than the answer cant be 3 or -3.
the number has to total to be larger than 3. again, since the absolute value turns the negatives into positives, then -4 is an acceptable answer. so the absolute value line should look like the above (please excuse the terrible look). I simplified it to the two numbers that start the equation. the two circle are open circles because the sign does not include an equal sign under it. you draw the arrows on either side of the two numbers because any answer beyond those arrows fits in with the equation
| 4 |
| 184728 |
| -4.5829492994929492949572728 |

did that answer the problem?

5 0
3 years ago
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