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4 years ago

Determine whether the set of data shown below display exponential behavior. Write yes or no explain why or why not?

Mathematics

1 answer:

joja [24]4 years ago

5 0

Answer:

I don't know what is your name is your

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What is 3÷-3 **three divided by negative three**

Reptile [31]

Answer:

-1

Step-by-step explanation:

It would be -1.

First, you can bring the negative sign outside, calculate 3 divided by 3 (which would be 1). Lastly, bring the negative sign back, so now you would have -1 as your answer.

7 0

3 years ago

The side lengths of a rectangle are all multiplied by 5. What happens to its perimeter?

stiv31 [10]

Answer:

The perimeter is multiplied by 5.

Step-by-step explanation:

Perimeter of a rectangle:

The perimeter of a rectangle with sides l and w is given by:

$P = 2(l + w)$

The side lengths of a rectangle are all multiplied by 5.

This means that $l = 5l, w = 5w$ . So

$P_M = 2(5l + 5w) = 2*5(l+w) = 10(l + w)$

What happens to its perimeter?

The rate is:

$\frac{P_M}{P} = \frac{10(l+w)}{2(l+w)} = 5$

The perimeter is multiplied by 5.

8 0

3 years ago

Whats the midpoint between -1,2 and -3,-4

iris [78.8K]

Answer:

md(-2,-1)

Step-by-step explanation:

Md=(x1+x2/2,y1+y2/2)

or,Md=(-1-3/2,2-4/2)

or,Md=(-4/2,-2/2)

•°•Md=(-2,-1)

3 0

3 years ago

Cody buys a soda that offers another soda free if he is lucky. The cap reads '1 in 6 wins!', meaning that each soda has a 1/6 pr

creativ13 [48]

Answer: 0.26

Step-by-step explanation:

Binomial probability formula :-

$P(X=x)=^nC_x\ p^x\ (1-p)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is total number of trials and p is the probability of getting success in each trial.

Given : The probability of winning = $\dfrac{1}{6}$

Let X be the random variable that represents the number of sodas.

Since he is guaranteed that he will win one soda .

If Cody buys 6 sodas, then the probability that he will win at least one more soda will be :

$P(x\geq2 )=1-(P(0)+P(1))\\\\=1-(^6C_0\ (\dfrac{1}{6})^0\ (1-\dfrac{1}{6})^{6-0}+^6C_1\ (\dfrac{1}{6})^1\ (1-\dfrac{1}{6})^{6-1})\\\\=1-((\dfrac{5}{6})^6+(\dfrac{5}{6})^5)\approx0.26$