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Nastasia [14]
3 years ago
15

Find the missing numbers then write each as a decimal 3/15=1/?=?/10

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0
3/15=1/5=2/10   and each one is equal to 0.2, I hope this helps cx
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Gorilla
harina [27]
The answer is true hopefully this helped
8 0
4 years ago
Mathematics achievement test scores for 300 students were found to have a mean and a variance equal to 600 and 3600, respectivel
Zina [86]

Answer:

(a) Approximately 205 students scored between 540 and 660.

(b) Approximately 287 students scored between 480 and 720.

Step-by-step explanation:

A mound-shaped distribution is a normal distribution since the shape of a normal curve is mound-shaped.

Let <em>X</em> = test score of a student.

It is provided that X\sim N(\mu = 600, \sigma^{2} = 3600).

(a)

The probability of scores between 540 and 660 as follows:

P(540\leq X\leq 660)=P(\frac{540-600}{\sqrt{3600} }\leq \frac{X-600}{\sqrt{3600} }\leq \frac{660-600}{\sqrt{3600} })\\=P(-1 \leq Z\leq 1)\\= P(Z\leq 1)-P(Z\leq -1)\\=0.8413-0.1587\\=0.6826

Use the standard normal table for the probabilities.

The number of students who scored between 540 and 660 is:

300 × 0.6826 = 204.78 ≈ 205

Thus, approximately 205 students scored between 540 and 660.

(b)

The probability of scores between 480 and 720 as follows:

P(480\leq X\leq 720)=P(\frac{480-600}{\sqrt{3600} }\leq \frac{X-600}{\sqrt{3600} }\leq \frac{720-600}{\sqrt{3600} })\\=P(-2 \leq Z\leq 2)\\= P(Z\leq 2)-P(Z\leq -2)\\=0.9772-0.0228\\=0.9544

Use the standard normal table for the probabilities.

The number of students who scored between 480 and 720 is:

300 × 0.9544 = 286.32 ≈ 287

Thus, approximately 287 students scored between 480 and 720.

3 0
3 years ago
Write the number 10 tens and 1 more
beks73 [17]
I believe the answer is 110
8 0
3 years ago
1. What is the formula for Pythagorean Theorem
Debora [2.8K]

Answer:

The formula is a^2 + b^2 = c^2

Step-by-step explanation:

A and B are legs and C is the hypothunisis.

The theorem is used for triangles.

4^2  + 5^2 = c^2

16 + 25 = c^2

41 = c^2

sqr(41) = sqr(c)^2

c = 6.403124237

4 0
3 years ago
Please help me!!! will mark brainlest
Licemer1 [7]

A. To be able to have the 2 sides ( the 2 triangles) line up correctly, Net A would be the correct one.


B. AB = 3

BC = 5

CD = 9.4



C. Surface area:

9.4 x 5 = 47

9.4 x 3 = 28.2

9.4 x 4 = 37.6

3 x 4 = 12


Total: 47 + 28.2 + 37.6 + 12 = 124.8 sq. in.

8 0
4 years ago
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