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Katen [24]
3 years ago
10

What can you know about the relationship between Escherichia coli and Entamoeba coli from their names?

Biology
1 answer:
Art [367]3 years ago
6 0
Both are microorganisms
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igomit [66]
Nucleoid

Is the answer for this
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3 years ago
Which of these BEST describes a scientific variable?
elena55 [62]

Answer: C) a factor that may affect an experiment or investigation

Explanation:

This is the best answer. A and B can be eliminated. D describes a controlled variable which is more specific than a scientific variable, thus C is the best answer. It is the best description of  just a scientific variable.

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. Many cities have “combined” sewers. In good weather, these systems funnel sewage to treatment plants. During rainstorms street
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Mutagens are chemical or physical agents that can alter the structure or sequence of DNA, causing mutations. Which of these is a
vova2212 [387]
D). Carcinogens are chemical factors in an organism's environment that can cause spontaneous mutation.
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3 years ago
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In an experiment, a certain colony of bacteria initially has a population of 50,000. A reading is taken every 2 hours, and at th
Iteru [2.4K]

Answer:

1) Recursive definition: p_n = (50,000)3^n

2) At the beginning of the 4th interval

Explanation:

1)

The initial population of the bacteria at time zero is

p_0 = 50,000

Here we are told that the reading is taken every two hours; we call this time interval "n", so

n=2 h

And also, after every time interval n, the number of bacteria has tripled.

This means that when n = 1,

p_1 = 3 p_0

And when n=2,

p_2 = 3 p_1 = 3(3p_0)=9 p_0

Applied recursively, we get

p_n = 3^n p_0

And substituting p0,

p_n = (50,000)3^n (1)

2)

Here we want to find at the beginning of which interval there are

p=1,350,000

bacteria.

This means that we can rewrite eq.(1) as

1,350,000=(50,000)3^n

By simplifying,

27=3^n

Which means that

n=3

However, this means that the number of bacteria is 1,350,000 after 3 time intervals; therefore, at the beginning of the 4th interval.

8 0
3 years ago
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