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djyliett [7]
3 years ago
13

Sonja wants to find the mass of her parakeet. What unit would be best to measure the bird’s mass?

Mathematics
1 answer:
Romashka [77]3 years ago
5 0

Answer:

Died speciman prior would be best to measure the bird’s mass.The length (also bill-to-tail length) of a bird is usually measured from dead specimens prior to their being skinned for preservation. The measurement is made by laying the bird on its back and flattening out the head and neck gently and measuring between the tip of the bill and the tip of the tail.

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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
4 years ago
What is the total area of the regions between the curves y = 6x2 − 18x and y = −6x from x = 1 to x=3?.
kvasek [131]

Using integration, it is found that the area between the two curves is of 22 square units.

<h3>What is the area between two curves?</h3>

The area between two curves y = f(x) and y = g(x), in the interval from x = a to x = b, is given by:

A = \int_{x = a}^{x = b} |f(x) - g(x)| dx

In this problem, we have that:

f(x) = 6x^2 - 18x, g(x) = -6x, a = 1, b = 3.

Hence, the area is:

A = \int_{1}^3 |6x^2 - 12x| dx

A = |x^3 - 6x^2|_{x = 1}^{x = 3}

Applying the Fundamental Theorem of Calculus:

A = |3^3 - 54 - 1^3 + 6|

A = 22

The area between the two curves is of 22 square units.

More can be learned about the use of integration to find the area between the two curves at brainly.com/question/20733870

8 0
3 years ago
Which of the following facts did you include in your explanation? Check all of the boxes that apply. The value of c could be 5 o
Marianna [84]
Check all of the answers
6 0
3 years ago
Question 1
xeze [42]

Step-by-step explanation:

Graphs of Exponential Functions

The graph passes through the point (0,1)

The domain is all real numbers.

The range is y>0.

The graph is increasing.

The graph is asymptotic to the x-axis as x approaches negative infinity.

The graph increases without bound as x approaches positive infinity.

The graph is continuous.

6 0
3 years ago
Read 2 more answers
Is 2/5 greater than less than equal to 2/3 * please tell me how to do the work! And not just tell the answer bc this is a test!*
Likurg_2 [28]

Answer:

2/5 is less than 2/3

Step-by-step explanation:

bc  the bottom number is how many in total and in 2/3 the number on the top only needs 1 more to be a whole.

3 0
3 years ago
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